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Q: How would you factor the problem 6x squared plus 79x plus 13?

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2x2 + 28xy + 98y2 = 2(x + 7)2.

It is: 3x*(x+7)

(4x + 1)(2x + 3)

n(2n - 1)(2n + 7)

If that's -18y2, the answer is (3x - 2y)(x + 9y)

Related questions

this problem cannot be factored

Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)

You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)

(x + 5)(x + 2)

(a + x^2)(b + y^2)

(a - 2)(a^2 + 6)

No

(x + 2)(x + 3)

(6x + t)(3x + t)

(a + 2 - b) (a + 2 + b)

4(x+y)^2

(3q + 2p)(9q + 7p)

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