Usually simple substitutions enable such expressions to be seen as quadratic expressions. The substitutions x = a2 and y = b2 give a4 + b4 - 7a2b2 = x2 - 7xy + y2 which does not have any rational factors. Consequently, the quartic in a and b does not have rational factors.
No. The golden ratio is approximately 1.618. The A4 paper uses something known as the Lichtenberg ratio 1:sqrt(2). If you cut a piece of A4 paper in half, the sides of the smaller sheets would maintain the same ratio. That's why A4 is exactly half the size of an A3 sheet, and A3 is exactly half of an A2 sheet, and so on.
If you mean a2 x a2... the answer is a4
Expand 4ab3 (a2b2-a-1)
Any sheet of paper in the An series - A4 being the most common size for printers and copiers.
( a2 ) ( a2+1 )
a5+b5 = (a+b) (a4-a3b+a2b2-ab3+b4)
the answer to factorising (a x a3 + 2ab + b2) would be (a4+2ab+b2)
All around Texas, a 'fully loaded' Audi A4 is going for a maximum of $44,100. If you're getting a price higher than that, you may want to look at what 'extras' the dealer is throwing in and make sure that's consistent with what you want in a 'fully loaded' Audi A4.
(a^2 + 8b)(a^2 - 5b)
Usually simple substitutions enable such expressions to be seen as quadratic expressions. The substitutions x = a2 and y = b2 give a4 + b4 - 7a2b2 = x2 - 7xy + y2 which does not have any rational factors. Consequently, the quartic in a and b does not have rational factors.
Fully synthetic. I go for Mobil 1
Unfortunately, limitations of the browser used by WA means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.
3a4 - 2a2 + 5a - 10 - 2a4 + 4a2 + 5a - 2 = a4 + 2a2 + 10a - 12 = a4 + (2a - 2)(a + 6)
not sure of your model but on the A4 2001 model on the dash board under the rev counter there is a plus and a minus sign plus increases the brightness and the minus reduces
The A4 is equipped with a tri-burst mechanism- it can fire 3 shots per trigger pull.
That looks simple enough for me; but if you want to factor it, you can use the formula for the difference of two squares.