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Factoring involves 'factoring out' the common numbers for each term. In a simple general form, a + ab = a(1+b).
It's like "undistributing" factors: instead of multiplying both terms by a number, you essentially divide both terms by a number.
In (7x + 49), both terms - 7x and 49 - have 7 as a factor. So, it can also be written:
7x + 49 = 7(x+7)
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What is the remainder when 2 is synthetically divided into the polynomial -3x2 plus 7x-9?
-7
What is the remainder when 2 is synthetically divided into the polynomial -3x2 plus 7x minus 9?
bghgbh
How do you factor x2 plus 7x plus 6?
x2 + 7x + 6 = (x + 6) (x + 1)
What is the factor trinomial 2x plus 7x plus 10?
10 + 9x
How do you solve -7x plus 6 plus 7x-2?
-7x + 6 + 7x - 2 = 4
What is the value of the discriminant of the polynomial 3x2-7x plus 4?
49-(4*3*4) = 1
Factor the polynomial below. x2 plus 7x plus 6?
It is: (x+1)(x+6) when factored
How do you factor 7x plus 49?
Factoring requires you to reduce as much as possible. To factor 7x + 49, you remove the common factor of 7x and 49, which is 7, and multiply (7x + 49)/7 (which is x + 7) by 7, without actually simplifying. 7x + 49 = 7(x + 7) Then, if possible, do the same thing until it cannot be further factored.
How do you factor the trinomial -x2 plus 7x plus 18 with each factor as a polynomial in descending order?
-((x + 2)(x - 9))
How do you factor the trinomial 5x2 plus 7x plus 2 with each factor as a polynomial in descending order?
(5x + 2)(x + 1)
Factor the polynomial 21x3-35x2 plus 14x?
21x3-35x2+14x = 7x(3x2-5x+2)
Factor the trinomial x2 plus 7x - 18 Enter each factor as a polynomial in descending order?
(X+9)(x-2)
How do you write each factor as a polynomial in descending order 5x square plus 7x plus 2?
(5x + 2)(x + 1)
How would you factor x3 plus 343?
(x + 7)(x2 - 7x + 49)
What is 7x plus 3y?
It's just a mathematical polynomial: 7x + 3y.
When dividing the polynomial x3 plus 5x2 plus 7x plus 3 by x plus 3 the remainder is 0 making x plus 3 a factor?
True.
Factor this polynomial 21x-18?
3(7x-6)
