(x + 7)(x2 - 7x + 49)
7x(3x3 - 2x2 + 5x + 1)
It is: 7(x+2y)
6x2 + 7x - 5 = (3x + 5)(2x - 1)
49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2
(x + 7)(x2 - 7x + 49)
7x2 plus 7x5 = 49
Factoring involves 'factoring out' the common numbers for each term. In a simple general form, a + ab = a(1+b). It's like "undistributing" factors: instead of multiplying both terms by a number, you essentially divide both terms by a number. In (7x + 49), both terms - 7x and 49 - have 7 as a factor. So, it can also be written: 7x + 49 = 7(x+7)
(3b + 7x)(3b + 7x) or (3b + 7x)2
7x + 7 = 7(x + 1)
1
56
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
49x²+70x+25 = (7x+5)² since the root (-70/(2*49)) of the quadratic equations is -5/7 (discriminant = 70²-4*49*25 = 0)
x2 + 7x + 6 = (x + 6) (x + 1)
7x(3x3 - 2x2 + 5x + 1)
49x2+28x+4 = (7x+2)(7x+2) when factored