(x + y)(x - 3y)
9 - x2 will factor into (3 - x)(3 + x)
x2-9x = x(x-9)
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
x2-49 = (x-7)(x+7)
X2 - 16(X - 4)(X + 4)============X2 + 16===========not factorable in real numbers
x2 - 4
9 - x2 will factor into (3 - x)(3 + x)
x2-14 does factor but not pretty; it factors to: (x+sqrt14)(x-sqrt14).
x2-3x-28
x2 + 6x - 2 can not be factored
x2-9x = x(x-9)
x2-x=x(x-1)
x2 - 13 + 30 = x2 + 17, which has no real factors.
x2-6x can be factored into x(x-6). Simply factor out the "x" from both factors.
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
That does not factor neatly.
Doesn't factor evenly