(x + y)(x - 3y)
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9 - x2 will factor into (3 - x)(3 + x)
x2-9x = x(x-9)
x2(x3 + 1) is the best you can do there.
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
x2-49 = (x-7)(x+7)