2x(y - 3) + 7(y - 3) = (2x + 7)(y - 3)
Do you mean 2x²? Assuming this is the case: 2x² - 3x + 8x - 12 = 2x² + 5x - 12 = (2x - 3)(x + 4)
if you want to factorise it then it will become (2x + 5)(x + 2) if it was equal to something then you would work it out differently. hope this helps
X3 + 8= (x+2)(x2-2x+4)
6x^3 + 3x = 3x(2x^2 + 1)
2x + 6 = 2(x+3)
It is: 4(2x+3m) when factorised
(x - 3)(2x - 7)
2x + 7 + 5 = 2x + 12 = 2*x + 2*6 = 2*(x+6)
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
(x-1)(2x+5)
8x + 20 = 4 (2x + 5)
It is 2(2x+3) when factorised
You cannot since the expression does not have rational roots.
17
2x + 12 = 2*x + 2*6 = 2*(x + 6)
6x^2 + 5x + 1 = (3x +1) (2x + 1)