6x2+5x+1 = (3x+1)(2x+1) when factored
1
Divide all terms by 3:- 2x2+5x-3 = (2x-1)(x+3) when factored
(3x + 4)(2x - 1) = 0 3x = -4 x = -4/3 2x = 1 x = 1/2 x = 1/2, -4/3
x + x = x(1+1)
There can be no answer since there is no equation: only an expression. It is possible to factorise the expression as follows: 6x2 - 5x - 11 = 6x2 + 6x - 11x - 11 = 6x(x + 1) - 11(x + 1) = (x + 1)(6x - 11) Just to add, if you meant 6x2 - 5x - 11 = 0, then the above factorise would give you either (x+1) = 0, or (6x-11)=0, so x=-1 or 11/6
6x2+5x+1 = (3x+1)(2x+1) when factored
One factor of 6x² + 5x - 11 is (x - 1).
(3x + 4)(2x - 1)
(x - 1)(x^2 - 5x + 2)
1
Divide all terms by 3:- 2x2+5x-3 = (2x-1)(x+3) when factored
......x^2-5x+2 ------------------------ x-1)x^3-6x^2+7x-2 ......x^3-x^2 -------------------------- ..............-5x^2+7x ..............-5x^2+5x ------------------------- ..........................2x-2 ..........................2x-2 -------------------------- .............................0 The quotient is x^2-5x+2
5x2 + 9x + 13 has no real factors.
5x-1+2= 5x+1
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
(3x + 4)(2x - 1) = 0 3x = -4 x = -4/3 2x = 1 x = 1/2 x = 1/2, -4/3