Ah, let's take a moment to appreciate the beauty of algebra. To factorise 6ab - 9ac, we can first factor out the greatest common factor, which is 3a. This leaves us with 3a(2b - 3c), where 2b - 3c is the factored expression. Just like painting a happy little tree, we've simplified our expression with a few gentle brushstrokes.
m(g-a)
In the same way that you would factorise any other expressions that do not contain an equality sign depending on the expressions of which none have been given.
5(3-2x)
2a(2b-c) :P
What about it? Factorise it?
a²-a = a(a-1)
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
you do (245x)
to put into brackets
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
6(t2s)
m(g-a)
It is the opposite of Expanding The Brackets
-5
qwertyuiopasdfjk
In the same way that you would factorise any other expressions that do not contain an equality sign depending on the expressions of which none have been given.
2(3n+4)