For example: 9x2-25 = (3x-5)(3x+5) but this only applies to negative expressions it wouldn't apply to 9x2+25
Factorise fully is when brackets are involved in the equation
m(g-a)
5(3-2x)
What about it? Factorise it?
For each of a list of algebraic expressions, find one or more common factors and factorise the expression.
Placing a question mark at the end of a list of expressions or numbers does not make it a sensible question. What do you want? To evaluate it (impossible), factorise it, something else?
For example: 9x2-25 = (3x-5)(3x+5) but this only applies to negative expressions it wouldn't apply to 9x2+25
Factorise fully is when brackets are involved in the equation
a²-a = a(a-1)
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
to put into brackets
you do (245x)
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
6(t2s)
m(g-a)
-5