If 6y-8 = 28 then y = 6
It is a quadratic expression and is (2y-1)(3y-4) when factored
What do 6, 9 and 12 have in common? 3. -6y / 3 = -2y +9x / 3 = +3x +12z / 3 = +4z Since they share 3, write 3 outside the brackets, and your solutions inside the brackets: 3(3x-2y+12z)
12y3 - 30y2 + 12yFactor out a y:y(12y2 - 30y + 12)Factor out a 6:6y(2y2 -5y + 2)Factor 2y2 - 5y + 26y(2y - 1)(y - 2)
With great difficulty in the absence of equality signs and minus or plus values for the given terms.
A = 3x2 + 9xy + 6y2l = 3x + 6yA = l×w∴ w = A/l∴ w = (3x2 + 9xy + 6y2) / (3x + 6y)∴ w = x + 1
The answer depends on the value of y. For example, when y = 0, 8y2 + 6y - 2 = -2 when y = 1, it is 12
It is 3(2y+5) when factorised
Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)
11
2y2(3y - 1)
If 6y-8 = 28 then y = 6
(x + 4y)(x - 6y)
To combine y^2 and 6y, you need to determine if they have any common factors. In this case, they do not have any common factors, so you cannot directly combine them. The expression y^2 + 6y is already simplified and cannot be further combined without additional terms or operations.
Collect like terms: 3x - x + 4x - 4y + 6y + 2 = 6x + 2y + 2
15y-15=0,y=1
What is 3x-6y=12