8x -12 ... 4(2x -3)
Do you mean 2x²? Assuming this is the case: 2x² - 3x + 8x - 12 = 2x² + 5x - 12 = (2x - 3)(x + 4)
4x2+8x+3 ------> (2x+3)(2x+1)
What about it? Factorise it?
-8x+3y=12 3y = 8x+12 y = (8/3)x + 4 So it will be a line with slope 8/3 and y intercept of 4
8x + 20 = 4 (2x + 5)
8x -12 ... 4(2x -3)
Do you mean 2x²? Assuming this is the case: 2x² - 3x + 8x - 12 = 2x² + 5x - 12 = (2x - 3)(x + 4)
(x+5)(x+3)
You don't. There is no way to factorise it.
j
12
If you mean: xsquared+8x-48 then it factors to (x-4)(x+12)
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
Doesn't factorise in integers. Roots are 0.84 and 7.16
It is: 4(2x+3m) when factorised
Use www.wolframalpha.com Enter factor 4x^2+8x-5 to receive the answer (2x-1)(2x+5)