You multiply all the numbers together.
6•3•4
There are 30 outfit possibilities. Normally for a problem like this you just have to multiply all the numbers, but the trick to this question is to first add the number of shirts. If you don't, then some of your outfits will be a sweater and dress shirt with no pants, which isn't an outfit. So you have a total of 10 shirts and 3 pairs of pants, and when you multiply them you get a total of 30 outfits.
160 outfits
15 outfits. Simple Math
Come out with your pants up
All i gotta say is keep it in your pants man
There are six possible combinations.
Assuming the shirts and pants are all different and that an "outfit" consists of one shirt and one pair of pants and that Jimmy is using these shirts and pants to make his outfits, there are 42 possible combinations.
There are 30 outfit possibilities. Normally for a problem like this you just have to multiply all the numbers, but the trick to this question is to first add the number of shirts. If you don't, then some of your outfits will be a sweater and dress shirt with no pants, which isn't an outfit. So you have a total of 10 shirts and 3 pairs of pants, and when you multiply them you get a total of 30 outfits.
160 outfits
15 outfits. Simple Math
24 seperate outfits.
How many different outfits are possible from six shirts, four pairs of pants, and five pairs of socks?
12 outfits
Assuming each of the shirts is distinguishable from the others and similarly with the pants and a "combination" consists of one shirt and one pair of pants, the answer is 4*10 = 40 combinations.
Assuming that you wear one of each every time (including a tie!), and that there are 3 pairs of boots, there are 4*3*2*3 = 72 combinations.
45 outfits
12