160 outfits
15 outfits. Simple Math
There are 30 outfit possibilities. Normally for a problem like this you just have to multiply all the numbers, but the trick to this question is to first add the number of shirts. If you don't, then some of your outfits will be a sweater and dress shirt with no pants, which isn't an outfit. So you have a total of 10 shirts and 3 pairs of pants, and when you multiply them you get a total of 30 outfits.
You multiply all the numbers together. 6•3•4
4 x 4 = 16
no many is not a conjunction and or and but are conjunctions
24 seperate outfits.
59
15 outfits. Simple Math
How many different outfits are possible from six shirts, four pairs of pants, and five pairs of socks?
12 outfits
Assuming the shirts and pants are all different and that an "outfit" consists of one shirt and one pair of pants and that Jimmy is using these shirts and pants to make his outfits, there are 42 possible combinations.
There are six possible combinations.
12
45 outfits
A lot
24
There are 30 outfit possibilities. Normally for a problem like this you just have to multiply all the numbers, but the trick to this question is to first add the number of shirts. If you don't, then some of your outfits will be a sweater and dress shirt with no pants, which isn't an outfit. So you have a total of 10 shirts and 3 pairs of pants, and when you multiply them you get a total of 30 outfits.