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Find the perimeter and area of a rectangle with width 3 meters and length 11 meters?
Oh, what a happy little rectangle we have here! To find the perimeter, we add up all the sides, which would be 2 times the width plus 2 times the length. So, 2(3) + 2(11) = 6 + 22 = 28 meters for the perimeter. And to find the area, we simply multiply the width by the length, which gives us 3 x 11 = 33 square meters of area. Just remember, there are no mistakes, only happy little accidents!
How do you prove the formula for the area of a triangle?
Easiest wayDraw a three inch by three inch square. add lines at one inch marks to form a small grid. draw line diagonally across to form two triangles. count the number of squares in one triangle (remember the squares with the diagonal line are only half a square)Did you get 4 1/2?A X B divided by two 3 X 3= 9 / 2 = 4.5To arrive to the forumla for area of triangle, lets look at the area of square and rectanlge first: Area of square: side x side Area of rectangle: length x width Notice that the formulas for area of square and rectangle is very similar. The squre is a special case only, so there is not much difference. Let's take the special case first- area of square: Area= side x side If I want to find the area of a triangle from this square, you have to divide the square in half diagonally. This means: (side x side)/2 = area of triangle Let's take a look at retangle now: Area of rectangle: length x width Similarly like the square, you divide the rectangle diagonally by half. This means: (length x width)/2 Conclusion: Thus, area of triangle= (base x height)/2 The base can be considered as one of the sides of the rectangle/square, and the height can be considered as the other side of the rectangle/square. THE FORMULA OF TRIANGLE COMES FROM HALF THE AREA OF RECTANGLE/SQUARE! Visit quickanswerz.com for more math help and tutoring!Area is measured in square units. If we are given a region we divide the region into unit squares.Then we count the number squares, which is the area of the region.Consider a rectangle of length 10 units and width 5 units.The area of the rectangle is 50 square units.It is because we can divide the rectangle into 10 equal parts along the length.Similarly, we can divide the rectangle into 5 equal parts along the width. Now we have divided the entire rectangle into unit squares.If we count the number of squares we get 50 unit squares.We get this by multiplying the length and the width. Area = Length*Width square units.This is the same for a parallelogram too.Area of a parallelogram is base * height square unitsThis is how the concept of area has come.We can find the area of the triangle also.A rectangle or a parallelogram can be divided into two equal triangles by a diagonal.Half of the area of the rectangle(or parallelogram) gives the area of the triangle.In fact, we can extend any triangle into an parallelogram.So, we get the formula, area of a triangle = (base* height)/2 square units.Source: www.icoachmath.com
How do you calculate the top dimensions of a rectangle if you know its perimeter and bottom area?
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
The width of a rectangle is 6 inches less than twice the length find the dimension of the rectangle if its area is 108 square inches?
Let the length of the rectangle be L and the width W, then W = 2L - 6 The area of a rectangle = L x W : 108 = L x (2L - 6) = 2L2 - 6L. Expressing this as a standard quadratic equation gives : 2L2 - 6L - 108 = 0. This can be factored as (2L + 12)(L - 9) = 0. As we are only concerned with positive solutions then the negative solution can be ignored, thus, When L - 9 = 0 then L = 9. As L = 9 then W = 2L - 6 = 18 - 6 = 12. The dimensions of the rectangle are : Width 12 inches, Length 9 inches.
How do you find volume when width and height is given?
Volume is a 3 dimensional attribute . Not only do you have to know the width and the height but also the length. If the width is, say, the diameter of a cylinder than you can easily find the area of the cross section (pi * r2) and multiply that by the height to get the volume.
How do I find the area of a rectangle if I only have the length?
You cannot find the area of a rectangle if you only know its length. You need to know its width too. Then you multiply its length by its width.
How do you find the length and width of a rectangle when you know the area?
you cannot do this; you have area only and two unknowns - lengthand width but only one equation: area = length x width
How do you find the area of a cylander?
-- Slice it down one side and flatten it out. -- Now you have a rectangle. You only have to find the area of a rectangle. -- The area of a rectangle is (length) times (width). -- The length of the rectangle used to be the length of the cylinder. -- The width of the rectangle used to be the circumference of the cylinder's round ends, while it was still rolled up.
Can you find the area of a rectangle only knowing the perimeter?
To find the area of a rectangle, you multiply the length by the width (one side by a different side) Or you could count how many centimeter squares make up the rectangle
How do you find the width of a rectangle knowing only the length?
the width is always shorter than the length. other than that, you would require more information about the rectangle (such as the area or the diagonal measurement) to ascertain the width
What is a smaller area of a rectangle with a width of 90 and a length of 130?
A rectangle has only one area - there no smaller or bigger area.
How do you find length and width of a rectangle when peremiter is given?
You really can't unless you know something else about the length or width or even the area of the rectangle. You have 2 unknowns (length & width) & only one equation (perimeter). In order to find 2 unknowns you need 2 equations, that's why you need to know something else about the rectangle such as how the length & width are related to each or the area of the rectangle. Hope that helps.
How do you find the perimeter of a rectangle with only the width or length and the area given?
It not possible you nit witt that is not true length x width = area If you know length and area, solve width width = area / length then 2 x length + 2 x width = perimeter
How do find the width of a rectangle when you only have the length?
you can't
How do you find the width and length of a rectangle if you only know the diagnol?
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
Area of rectangle is 1740.5 FT2 and length is 59 ft Find the width?
The area of a rectangle is always the product of its length and its width. Call the unknown width w. Then 59w = 1740.5; w = 29.5 feet to the maximum possible number of justified significant digits. (59 has only two.)
What is the area of a rectengle 14cm by 12cm?
The area of EVERY rectangle is the product of (length) times (width).Knowing that, you can now find the area of not only that particular rectangle,but also every rectangle you ever encounter for the rest of your life.Man, you are empowered !
