Q: How do you find the width of a rectangle knowing only the length?

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You divide the perimeter by the width and you get the lenght

With Pythagoras' theorem: diagonal2- length2 = width2

If by that you mean knowing only the diagonal and the width, then by the formula a2+b2=c2, where a is the length, b the width and c the diagonal. To find the width b, you need to calculate sqrt(c2-a2). For example, the width of a rectangle with length 3 and diameter 5 is sqrt(52-32)=4

the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle

You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.

Related questions

You divide the perimeter by the width and you get the lenght

With Pythagoras' theorem: diagonal2- length2 = width2

If by that you mean knowing only the diagonal and the width, then by the formula a2+b2=c2, where a is the length, b the width and c the diagonal. To find the width b, you need to calculate sqrt(c2-a2). For example, the width of a rectangle with length 3 and diameter 5 is sqrt(52-32)=4

the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle

You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.

the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle

For a rectangle or square, Area = Length * Width So Length = Area / Width.

length times width

Area of rectangle divided by its length = width of rectangle