The domain is the set of values that x may take that gives back an answer that makes sense. The range is the set of values that are possible results of the function.
the "log" function does not accept 0 or negative values on its domain and returns negative, zero and positive numbers (ie all real values).
The next function does not appear properly but you could figure it out
Yes.
If you mean y = 5x-13 then in standard form it is 5x-y-13 = 0
5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
The ordered pair (0, -6) Ordered pairs look like (x, y). they are the coordinates of a point on your graph. Asking if (0,6) is a solution to your equation means, does this point lie on the graph? Or algebraically, if you substitute in x = 0 and y = -6 into the equation, does it work? y = 5x-7 -6 = 5(0) -7 -6 = 0 - 7 -6 = -7 Well, -6 does NOT = -7, so we know that this ordered pair is not a solution to the function.
y5x-1y5x=1y=1/5xTherefore the gradient is 1/5x
7
y=5x-3
Since there is no inequality sign, those are not inequalities. An inequality sign is normally one of the following: greater than; less than; great-or-equal; less-than-or-equal.
Yes.
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If you mean y = 5x-13 then in standard form it is 5x-y-13 = 0
If you mean y = 5x-3 then it is the linear equation of a straight line
6
If you mean: y = 5x+6.50 then it is a straight line equation whose slope is 5 with a y intercept of 6.5
If you mean: y = 5x+16 then the y intercept is 16 and the slope is 5
If you mean: y = 5x then it has a slope of 5 and passes through the origin of (0, 0)