Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
Usually at the minimum or maximum of a function, one of the following conditions arises:The derivative is zero.The derivative is undefined.The point is at the end-points of the domain that is being considered (or of the naturally-defined domain, for example, zero for the square root).This will give you "candidate points"; to find out whether each of these candidate points actually is a maximum or a minimum, additional analysis is required. For example, if the second derivative is positive, you have a minimum, if the second derivative is negative, you have a maximum - but if it is zero, it may be a maximum, a minimum, or neither.
If the domain is infinite, any polynomial of odd degree has infinite range whereas a polynomial of even degree has a semi-infinite range. Semi-infinite means that either the range has a real minimum but no maximum (ie maximum = +infinity) or that it has a real maximum but no minimum (ie minimum = -infinity).
A maximum or minimum is generally referred to as an extrema.
In theory you can go down the differentiation route but because it is a quadratic, there is a simpler solution. The general form of a quadratic equation is y = ax2 + bx + c If a > 0 then the quadratic has a minimum If a < 0 then the quadratic has a maximum [and if a = 0 it is not a quadratic!] The maximum or minimum is attained when x = -b/2a and you evaluate y = ax2 + bx + c at this value of x to find the maximum or minimum value of the quadratic.
By taking the derivative of the function. At the maximum or minimum of a function, the derivative is zero, or doesn't exist. And end-point of the domain where the function is defined may also be a maximum or minimum.
The minimum is the vertex which in this case is 0,0 or the origin. There isn't a maximum.....
Find the maximum and minimum values that the function can take over all the values in the domain for the input. The range is the maximum minus the minimum.
You cannot. The function f(x) = x2 + 1 has no real zeros. But it does have a minimum.
In Calculus, to find the maximum and minimum value, you first take the derivative of the function then find the zeroes or the roots of it. Once you have the roots, you can just simply plug in the x value to the original function where y is the maximum or minimum value. To know if its a maximum or minimum value, simply do your number line to check. the x and y are now your max/min points/ coordinates.
the maximum or minimum value of a continuous function on a set.
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
It can't - unless you analyze the function restricted to a certain interval.
Set the first derivative of the function equal to zero, and solve for the variable.
y=2x2-3x2-12x+5=0
Yes.
You can detect the brightest point in an image using the minMaxLoc function in OpenCV. This function will return the minimum and maximum pixel intensity values, as well as the coordinates of the minimum and maximum values. By retrieving the coordinates of the maximum value, you can locate the brightest point in the image.