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Earn +20 ptsQ: How do you find the mode when only three numbers are repeated twice?
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How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
The numbers are 14, 16 and 18.
The sum of two numbers is 84 One number is three times the other Find the numbers?
The numbers are 21 and 63.
Find three consecutive numbers whose product is 15600?
24,25,26
The difference of two positive numbers is 16. One number is 3 times the other. Find the two numbers?
If the higher is 3 times the lower, the difference must be twice the lower so the numbers are 8 and 24.
How do you find three consecutive integers so that twice the first increased by three times the third will be -24?
The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.
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