1. Find the mean (average) of each set.
2. Subtract each value from its set mean.
3. Square each difference.
4. Add the squared values for each set.
The sum of the squared differences for each set is that set's variance. If you want to find standard deviation (a much more useful number in most cases), divide the variance by the number of values in the set minus 1 (n-1), and then take the square root of the result.
You cannot. The numbers 2 and 12 have hcf = 2 and LCM = 12 The numbers 4 and 6 also have hcf = 2 and LCM = 12 So if you just knew the hcf and LCM you would not know which of the two was the required pair.
You can make lots of sets that contain the number 74, for example:{74} {73, 74, 75} {0, 74, 8, 99} The set of integers The set of real numbers The set of complex numbers
A pattern formed by 2 sets of numbers.
There are infinitely many sets: Some examples: {346}, or {346, sqrt(2), pi, -3/7}, or all whole numbers between 43 and 530, or multiples of 2, or composite numbers, or counting numbers, or integers, or rational numbers, or real numbers, or complex numbers, etc.
Standard deviation and variance
it has to have 2 sets of numbers
5.142857143 is the mean.12.43956044 is the variance.3.526976104 is the standard deviation.
Example: GCF of 6 and 12= 2 Example 2: GCF of 54 and 6=9 List all the factors of the numbers you use, then if the numbers you have when you list the factors have the same number in both sets of numbers, that is your GCF
Variance = sigma((value - mean)2) / (# values - 1) Mean = (0+1+1+2)/4 = 1 Variance = ((0-1)2+(1-1)2+(1-1)2+(2-1)2)/(4-1) Variance = (1+0+0+1)/3 Variance = 2/3 Variance ~ 0.667
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
-3
There are infinitely many sets of this type. Some of the common sets include natural numbers, integers, rational numbers, real numbers, complex numbers. Also, as an example, all sets of multiples of some whole number, for instance: { ... -6, -4, -2, 0, 2, 4, 6, ...} {... -9, -6, -3, 0, 3, 6, 9, ...} etc.
The variance of 2 3 5 12 = 20.3333
Find 2 numbers
The variance is 27.0
You cannot. The numbers 2 and 12 have hcf = 2 and LCM = 12 The numbers 4 and 6 also have hcf = 2 and LCM = 12 So if you just knew the hcf and LCM you would not know which of the two was the required pair.
var(X) = (xm/a - 1)2 a/a-2 . If a < or equal to 2, the variance does not exist.