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The y-intercept can be obtained from the straight line formula, y=mx+c. The y-intercept, c, is therefore given by c=-mx+y where m is the coefficient of gradient.
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What is a slope used for?
It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
What are the slope and yintercept of line 5x 10y 15?
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
What would the equation of a line be if it went through the point 2 comma 2 and its yintercept was 10?
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
What is the equation in slope-intercept form of the line that has a slope of 5 and y-intercept of -3?
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Why do you find median?
You find the median to find the middle number
What is the slope and yintercept of y plus 4x plus 3?
There is no slope nor intercept because there is no equation, simply an expression.
What is a slope used for?
It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
How do you write an equation of a line that passes through the xintercep and yintercept?
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
What are the slope and yintercept of line 5x 10y 15?
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
How do you find the slope and y-intercept of an equation?
first of all, i dont see how slope and yintercept has anything to do with shopping. usually in an equation, y= mx+b, m stands for slope, and b is the y-intercept. x and y are just x and y. If the equation is mixed up, and is not in y=mx+b format, you need to solve to get y on one side, the slope, x, and whatever the presented constant is (which is the y-intercept) on the other side. hope this helps.
What would the equation of a line be if it went through the point 2 comma 2 and its yintercept was 10?
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
What is the equation in slope-intercept form of the line that has a slope of 5 and y-intercept of -3?
8
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