2x+5y=10
is the same as
5y=-2x+10
Now divide both sides by 5
y=-2/5x+2
So the graph is a line with y intercept of 2 and slope of -2/5.
Let's find at least 3 points in order to draw the graph of y = -(2/5)x + 2.
y-intercept = 2 yields the point (0, 2)
y = 0 yields the point (5, 0) which is the x-intercept.
x = -1 yields the point (-1, 2.4)
x = 1 yields the point (1, 1.6)
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Now you can graph the line that passes through the points that you obtained.
It's a straight from (0/2) to (5/0).
2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation.
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
what is the solution of x-5y=10 and 2x-10y=20
Without an equality sign and not knowing the plus or minus value of 5y the given terms can't be considered to be a straight lie equation.
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4
11x + 5y
It is an expression that can be simplified to 5y+2x-6
2X - 5Y = 10 ???? If so. 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
6x plus 3y minus 2x plus 5y equals 4x plus 8y.
2x + 3y - x + 5y combine the like terms 2x - x + 3y +5y simple arithmetic x + 8y
To solve this, present the equation in the standard slope/intercept form of y = mx + c. 'm' is the slope. 2x + 5y = 10 5y = -2x + 10 y = -2/5x + 2 Therefore, -2/5 is the slope.
(4, -1)
(5, 0)