2x+5y=10
is the same as
5y=-2x+10
Now divide both sides by 5
y=-2/5x+2
So the graph is a line with y intercept of 2 and slope of -2/5.
Let's find at least 3 points in order to draw the graph of y = -(2/5)x + 2.
y-intercept = 2 yields the point (0, 2)
y = 0 yields the point (5, 0) which is the x-intercept.
x = -1 yields the point (-1, 2.4)
x = 1 yields the point (1, 1.6)
.
.
Now you can graph the line that passes through the points that you obtained.
It's a straight from (0/2) to (5/0).
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2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation.
what is the solution of x-5y=10 and 2x-10y=20
Without an equality sign and not knowing the plus or minus value of 5y the given terms can't be considered to be a straight lie equation.