0 = -2x + 5y - 15 -5y = -2x - 15 y = 2x/5 + 3
They are at coordinates of: (0, -6) and (15, 0) respectively
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
what is the solution of x-5y=10 and 2x-10y=20
2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
-2
(5, 0)
If you mean 2x+5y = -10 then the y intercept is -2
0 = -2x + 5y - 15 -5y = -2x - 15 y = 2x/5 + 3
To solve this, present the equation in the standard slope/intercept form of y = mx + c. 'm' is the slope. 2x + 5y = 10 5y = -2x + 10 y = -2/5x + 2 Therefore, -2/5 is the slope.
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
2X - 5Y = 10 ???? If so. 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
2x + 5y = 10Subtract 2x from each side:5y = -2x + 10Divide each side by 5:y = - (2/5)x + 2Slop = - (2/5)Y-intercept = 2
They are at coordinates of: (0, -6) and (15, 0) respectively