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In Cartesian coordinates in two dimensions: plot the intercept (if it is the X intercept it is usually plotted on the horizontal axis; the Y intercept is usually plotted on the vertical axis). From the intercept plot the slope (that is the rise Y increase [up] divided by the X increase [to the right]).

Example: Y intercept -4; slope +1,5

Plot the point (0;-4) [four units below the origin]

from there go 1,5 units up and 1 unit right to (1;2,5) plot a point there

Connect the points and extend the line

Note you might get better accuracy if you spread your points out, in the example you should make sure the line extension goes through the point (10;11) [fifteen units up and ten units over from the intercept]

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Q: How do you graph an equation using slope and intercepts?
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What are the steps to graph an equation of a line using the intercepts?

Draw the axes. Plot the two intercepts. Draw a line connecting the two points


How do you graph 3x plus 4y equals -4?

3x+4y=-4 can be graphed on a graphing calculator or by changing the form of the equation from standard form to slope intercept form. Rearrange the equation 4y=-3x-4 divide by 4 y=(-3/4)x-1 Now, you can simply graph the equation using the y intercept and the slope of the equation. A good point to start with is (0,-1) you know this point is the y intercept because of the standard y intercept equation y= mx+b where b is the y intercept and m is the slope. From the y intercept of (0,-1) you can then graph using the slope which is the change of y over change in x. So you would move up 3 and to the left 4 since the slope is negative. You can also move down three and to the right 4. Then continue, this process until you have the equation graphed. It should be a straight line.


How do you graph using the rate of change and initial value?

Normally on the Cartesian plane using as for example the straight line equation y = mx+c whereas m is the gradient or slope and c is the y intercept.


What is a sentence using the word graph?

The graph showed the results from his experiment. You can graph the data points to see what type of curve your equation defines.


Can you write a linear equation in the slope intercept form using the points (34) and (58)?

If you mean points of (3, 4) and (5, 8) then the slope is 2 and the equation is y=2x-2

Related questions

How do you find slope using x and y intercepts?

Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.


What are the steps to graph an equation of a line using the intercepts?

Draw the axes. Plot the two intercepts. Draw a line connecting the two points


What is the equation for a vertical line using y equals?

y= mx + b. M is the slope of the line, when b is where the line intercepts the y axis.


Why is slope form important?

Slope form gives you a clear image of the graph automatically as soon as you see the equation. In any given equation y=mx+b, m is the slope, which helps you visualize how steep the graph is and in which direction it goes (increases or decreases). b is the y-intercept, which is just a fancy term for where the graph intersects the y-axis. Using slope form helps you graph the graph way easier than using another form, such as standard form (Ax+By=C. What a mess!).


What are the x-intercepts of the graph of y equals 12x2 - 5x - 2?

Using the quadratic equation formula: x = -1/4 and x = 2/3


How do you graph y x 2?

It is a line. There are many ways to graph it using intercepts etc. But, you can pick some x points, plug them in your equation, and find the corresponding y point, The graph those (x,y) values


How do you graph a line using slope intercept form of a linear equation?

you create ordered pairs or a serious of (x,y) points on the graph which you can plot and connect with a straight line


How do you graph this function using algebra y equals 1x-4?

it is a straight line equation with a slope of 1 and a y intercept of -4


When you graph a line using only the slope and a point what step do you start with?

When you graph a line using only the slope and a point, you start by graphing the point.


A linear equation cannot always be graphed by using intercepts alone?

Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.


How do you graph 3x plus 4y equals -4?

3x+4y=-4 can be graphed on a graphing calculator or by changing the form of the equation from standard form to slope intercept form. Rearrange the equation 4y=-3x-4 divide by 4 y=(-3/4)x-1 Now, you can simply graph the equation using the y intercept and the slope of the equation. A good point to start with is (0,-1) you know this point is the y intercept because of the standard y intercept equation y= mx+b where b is the y intercept and m is the slope. From the y intercept of (0,-1) you can then graph using the slope which is the change of y over change in x. So you would move up 3 and to the left 4 since the slope is negative. You can also move down three and to the right 4. Then continue, this process until you have the equation graphed. It should be a straight line.


Can all the linear equations be graph using the intercept?

Yes - provided you allow both x and y intercepts.