How do you graph x-3y equals 6 on a graph?

Answer 1

The first step would be to get x-3y=6 out of standard form and into y=mx+b form, where m is the slope and b is the y-intercept. To do this, we need to get y by itself on one side.

x-3y=6

-x -x

-3y=-x+6

Divide -3 on both sides to give us y=(1/3)x-2

Now that this is in y=mx+b form, we can properly graph this line. First, you have to plot the y-intercept on the graph, which is -2 on this line. The point will be (0,-2), and once this is plotted, we can finish the rest of our line.

To get other points, we can use the "m," or the slope, which is (1/3). Take your point and go up one, over to the right three and plot a point. Keep going up one, over to the right three until enough points are plotted. Take a straight edge and connect the points. You have now successfully graphed this line.

(You can also go down one, to the left three, since that is the same as (-1/-3), which equals (1/3))