it will form a parabola on the graph with the vertex at point (0,0) and points at (1,1), (-1,1), (2,4), (-2,4)......
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(2, -2)
Y = 4/x^2
No, to be linear, both the power of x and y need to be 1. Since x is squared, the power of x is 2.
If you are solving for y, it is fine. If you are solving for x, divide both sides by x and the equation should be x = y/x
y=xsquared-4x+2