You're essentially trying to calculate the diameter of a cylinder with a hole in the middle. There are two formulas for volume which you need.
Volume= Pi * r2 * h (where Pi=3.142, r = radius of the coil, h = width of the coil)
Volume= Weight/Density
Since both these formula equal Volume:
Weight/Density= Pi * r2 * h
Since the weight you have is for a cylinder with a hole in it, you need to calculate the volume of the whole cylinder (without the hole) and subtract the volume of the hole. So for a steel coil
Weight/Density = (Pi * rc2 * h)-(Pi * rh2 * h)
where rc= the radius of the coil and rh = the radius of the hole (Radius=diameter/2)
you're trying to calculate the radius of the coil, so rearrange the formula to get:
((Weight/Density)/Pi*h) + rh2 = rc2
The diameter of the coil = 2 *rc
NOTE:- It's important to keep your units of measure consistent throughout the calculation. Density is generally represented by kilograms per cubic metre (kg/m3) - for us metric users ;-) Therefore keep your coil weight in kgs and your radius / width measures in metres.
Weight = {(3.1416 (0.025)^2) / 4 }* 7850 kg/m^3 * 1m = 3.85336 kg/.
You calculate the volume then multiply by the density of the glass. The volume is 1 x 1 x .006 = .006 cu meters Density depends on glass type but is generally about 2200 kg/cu meter Weight = .006 x 2200 = 13.2 Kg
The amount of energy is given by the formula for gravitational potential energy:GPE = mgh That is, it depends on mass, gravity, and height.
Tare weight is the weight of the empty container. A tare function enables a scale to account for the weight of the container and display only the additional weight of the contents.
weight x distance = work
To calculate the outside diameter of a roll of carpet, you can use the following formula: Outside Diameter (in inches) = √[(Weight in pounds / (Width in feet x Length in feet)) * 32] In your case: Weight = 1000 pounds Width = 12 feet Length = 180 feet Outside Diameter (in inches) = √[(1000 / (12 x 180)) * 32] Outside Diameter ≈ √[(1000 / 2160) * 32] Outside Diameter ≈ √(0.1481 * 32) Outside Diameter ≈ √4.7392 Outside Diameter ≈ 2.18 inches So, the outside diameter of a 1000-pound roll of carpet that is 12 feet by 180 feet is approximately 2.18 inches.
Height and diameter will give you the volume, if you know the density you can then calculate weight from that.
Dimensions: Inside Diameter Of Mouth Opening: 1.4in (36mm)Outside Diameter Of Mouth Opening: 2.1in (53mm)Height: 19in (48.3 cm)Diameter: 10.5in (26.67 cm) at widest point
D=Diameter L=Length ={(D^2)/(162)*L}
Typical weight and dimensions of PVC and CPVC pipes are indicated in the table below:PVC and CPVC Pipes - Schedule 40Nominal Pipe Size(inches)Outside Diameter(inches)Minimum Wall Thickness(inches)Nominal Inside Diameter(inches)Weight(lb/ft)PVCCPVC1/20.8400.1090.6220.160.173/41.0500.1130.8240.210.2311.3150.1331.0490.320.341 1/41.6600.1401.3800.430.461 1/21.9000.1451.6100.510.5522.3750.1542.0670.680.742 1/22.8750.2032.4691.071.1833.5000.2163.0681.411.5444.5000.2374.0262.012.2055.5630.2585.0472.7366.6250.2806.0653.533.8688.6250.3227.9815.395.811010.7500.36510.0207.558.241212.7500.40611.93810.0110.891414.0000.43813.12411.801616.0000.50015.00015.43PVC and CPVC Pipes - Schedule 80Nominal Pipe Size(inches)Outside Diameter(inches)Minimum Wall Thickness(inches)Nominal Inside Diameter(inches)Weight(lb/ft)PVCCPVC1/20.8400.1470.5460.200.223/41.0500.1540.7420.270.3011.3150.1790.9570.410.441 1/41.6600.1911.2780.520.611 1/21.9000.2001.5000.670.7422.3750.2181.9390.951.022 1/22.8750.2762.3231.451.5633.5000.3002.9001.942.0944.5000.3373.8262.753.0555.5630.3754.8133.8766.6250.4325.7615.425.8288.6250.5007.6258.058.831010.7500.5939.56412.0013.091212.7500.6871137616.5018.01414.0000.75012.50019.301616.0000.84314.31425.441 lb = 0.4536 kg1 ft (foot) = 0.3048 m1 in (inch) = 25.4 mm
Without knowledge of the material you cannot.
You need to specify the wall thickness in order to calculate the weight.
weight of all steel can be calculated by multiplying unit volume with density.
Static pressure is .434 X height Example 10 ft x .434 4.34 PSI to prove take 2.31 PSI x 4.34 To find FORCE to need to calculate the diameter of the piping and the height and then the weight of the water inside the pipe
Firstly, calculate the molecular volume by dividing the product of molecular density and the molecular weight by the Avogadro number. Then take a third root of the volume, the found value is the atomic radius. Then multiply it by 2 to find the diameter.
You can't. In addition to the cylinder's diameter, the pressure at its base also depends on the density and depth of the fluid in the cylinder ... which gives you the weight of fluid resting on the base area. The pressure alone is not enough information to allow you to calculate the diameter.
Engineering requires calculation of the dish end diameter and circumference for proper fit before crimping. The weight can also be necessary in some applications. To determine the weight, knowing the substance and dimension, going to weight of unit of substance the calculation can be determined.