You're essentially trying to calculate the diameter of a cylinder with a hole in the middle. There are two formulas for volume which you need.
Volume= Pi * r2 * h (where Pi=3.142, r = radius of the coil, h = width of the coil)
Volume= Weight/Density
Since both these formula equal Volume:
Weight/Density= Pi * r2 * h
Since the weight you have is for a cylinder with a hole in it, you need to calculate the volume of the whole cylinder (without the hole) and subtract the volume of the hole. So for a steel coil
Weight/Density = (Pi * rc2 * h)-(Pi * rh2 * h)
where rc= the radius of the coil and rh = the radius of the hole (Radius=diameter/2)
you're trying to calculate the radius of the coil, so rearrange the formula to get:
((Weight/Density)/Pi*h) + rh2 = rc2
The diameter of the coil = 2 *rc
NOTE:- It's important to keep your units of measure consistent throughout the calculation. Density is generally represented by kilograms per cubic metre (kg/m3) - for us metric users ;-) Therefore keep your coil weight in kgs and your radius / width measures in metres.
Weight = {(3.1416 (0.025)^2) / 4 }* 7850 kg/m^3 * 1m = 3.85336 kg/.
You calculate the volume then multiply by the density of the glass. The volume is 1 x 1 x .006 = .006 cu meters Density depends on glass type but is generally about 2200 kg/cu meter Weight = .006 x 2200 = 13.2 Kg
The amount of energy is given by the formula for gravitational potential energy:GPE = mgh That is, it depends on mass, gravity, and height.
Tare weight is the weight of the empty container. A tare function enables a scale to account for the weight of the container and display only the additional weight of the contents.
weight x distance = work
To calculate the outside diameter of a roll of carpet, you can use the following formula: Outside Diameter (in inches) = √[(Weight in pounds / (Width in feet x Length in feet)) * 32] In your case: Weight = 1000 pounds Width = 12 feet Length = 180 feet Outside Diameter (in inches) = √[(1000 / (12 x 180)) * 32] Outside Diameter ≈ √[(1000 / 2160) * 32] Outside Diameter ≈ √(0.1481 * 32) Outside Diameter ≈ √4.7392 Outside Diameter ≈ 2.18 inches So, the outside diameter of a 1000-pound roll of carpet that is 12 feet by 180 feet is approximately 2.18 inches.
Height and diameter will give you the volume, if you know the density you can then calculate weight from that.
To calculate weight or mass when diameter and height are given, you first need to calculate the volume of the object using the formula for the volume of the shape (e.g., cylinder, sphere). Once you have found the volume, you can then calculate the weight or mass by multiplying the volume by the density of the material. Weight can be calculated using the formula Weight = mass x gravity.
D=Diameter L=Length ={(D^2)/(162)*L}
Typical weight and dimensions of PVC and CPVC pipes are indicated in the table below:PVC and CPVC Pipes - Schedule 40Nominal Pipe Size(inches)Outside Diameter(inches)Minimum Wall Thickness(inches)Nominal Inside Diameter(inches)Weight(lb/ft)PVCCPVC1/20.8400.1090.6220.160.173/41.0500.1130.8240.210.2311.3150.1331.0490.320.341 1/41.6600.1401.3800.430.461 1/21.9000.1451.6100.510.5522.3750.1542.0670.680.742 1/22.8750.2032.4691.071.1833.5000.2163.0681.411.5444.5000.2374.0262.012.2055.5630.2585.0472.7366.6250.2806.0653.533.8688.6250.3227.9815.395.811010.7500.36510.0207.558.241212.7500.40611.93810.0110.891414.0000.43813.12411.801616.0000.50015.00015.43PVC and CPVC Pipes - Schedule 80Nominal Pipe Size(inches)Outside Diameter(inches)Minimum Wall Thickness(inches)Nominal Inside Diameter(inches)Weight(lb/ft)PVCCPVC1/20.8400.1470.5460.200.223/41.0500.1540.7420.270.3011.3150.1790.9570.410.441 1/41.6600.1911.2780.520.611 1/21.9000.2001.5000.670.7422.3750.2181.9390.951.022 1/22.8750.2762.3231.451.5633.5000.3002.9001.942.0944.5000.3373.8262.753.0555.5630.3754.8133.8766.6250.4325.7615.425.8288.6250.5007.6258.058.831010.7500.5939.56412.0013.091212.7500.6871137616.5018.01414.0000.75012.50019.301616.0000.84314.31425.441 lb = 0.4536 kg1 ft (foot) = 0.3048 m1 in (inch) = 25.4 mm
Without knowledge of the material you cannot.
You need to specify the wall thickness in order to calculate the weight.
Dimensions: Inside Diameter Of Mouth Opening: 1.4in (36mm)Outside Diameter Of Mouth Opening: 2.1in (53mm)Height: 19in (48.3 cm)Diameter: 10.5in (26.67 cm) at widest point
weight of all steel can be calculated by multiplying unit volume with density.
To calculate the weight of a bronze pipe, you need to know the dimensions (length, outer diameter, and wall thickness) of the pipe. Then, you can use the formula: weight = (outer diameter - wall thickness) x wall thickness x length x density of bronze. Finally, multiply the result by the density of the bronze material to get the weight.
To calculate the weight of an aluminum rod in inches, you would need to know the density of aluminum (which is about 0.098 lbs/in^3) and the volume of the rod (which can be calculated using its length and diameter). You can then multiply the volume by the density to find the weight of the aluminum rod.
You calculate its volume, look up the density of bronze, then multiply volume x density to get mass. Probably that's what you want; if you really want weight, you multiply mass x gravity to get the weight.