An equation is a function if it is in y=mx+b form or has a y= in foront of it. f(x) is a classic way of writing a function. Ex) X^2 is a function
Either - or both - can be true.
The normal way of showing that y is a function of x is to write y = f(x).
A function of x means that the answers depends on the value of x that is substituted into the function. For example: y = x + 1 If x = 1, y = 2 If x = 2, y = 3 and so on.
The x- and y-intercepts of a function are the points at which the graph of the function crosses respectively the x- and y-axis (ie. y=0 and x=0).
An equation is a function if it is in y=mx+b form or has a y= in foront of it. f(x) is a classic way of writing a function. Ex) X^2 is a function
A function is an equation that gives a unique answer. A relation does not. Example: y = 3x + 1 is a function. If I give you x, you can determine y. And that y is unique to that x. So if x = 1, you know y = 4. No other of x gives y = 4 as an answer. So y = 3x + 1 is a function. Example: y = 4x2. So if I give you x = 1, y = 4. But y = 4 if I also give you x = -1. So y = 4x2 is not a function, it is a relation.
Suppose the function, y = f(x) maps elements from the domain X to the range Y. Thenfor every element x, in X, there must be some element y in Y, andfor an element y, in Y, there can be at most one x in X.
The inverse of the function y = x is denoted as y = x. The inverse function essentially swaps the roles of x and y, so the inverse of y = x is x = y. In other words, the inverse function of y = x is the function x = y.
The function is f(x, y) = x/y where x, y are real, and y ≠0
y = x This is a line and a function. Function values are y values.
You have Y and you have X. F=function. Y is already a function of X because here's another way you write Y: F(X). So instead of putting Y you out F(X) which meanf "F or X" or "function of X".
A binary function is a function f if there exists sets X, Y, and Z, such that f:X x Y -> Z where X x Y is the cartesian product of X and Y.
implicit function/? an equation the function(x,y)=0 defines y implicitly as a function of x the domain of that implicitiy defines function consists of those x for which there is a unique y such that the function (x,y)=0
Either - or both - can be true.
Both. If you look at it like this: y=41-x you say x is independent and y is dependent of x (i.e. y is a function of x) For x=41-y you say y is independent and x is dependent of y (i.e. x is a function of y)
'Y' is a function 'f' of 'x': Y = f(x) . 'Z' is a function 'g' of 'y': Z = g [ f(x) ] .