answersLogoWhite

0


Best Answer

34/(1 + 2)

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you make 27 using 1 2 3 and 4 only once?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How do you make 27 from 1 3 4 9 using each number once and only addition multiplication and division?

[Impossible].


How do you make 27 from 1 3 4 and 9 Using each number only once?

3^((4+1)/9)=35/9=243/9=27


How do you get to 27 using the numbers 1 2 4 and 6 only once?

(6*4)+2+1 = 27


How do you make 27 using 1 2 3 and 4 once?

3*(2*4 + 1) = 3*(8 + 1) = 3*9 = 27


How many times does 27 go into 27?

Once only


Sharon uses her initials SLF for her password How many different three-letter passwords can she make with these letters?

Six if using each letter once, or 27 if using a letter more than once.


Who can solve this - Using 1 3 4 and 9 make 27 each number can only be used once and must be used using the following functions plus - x and divide?

This is for a job application...but I think it's impossible. Any takers with an answer?


How do you make 27 using the numbers 1234?

32 -(1+4) =27


How many combinations can you make using only the numbers 1-7?

8


How can you get the number 31 using 9 9 6 3 and 2 only using them once each?

9*9/3 + 6 - 2 = 9*3 + 6 - 2 = 27 + 6 - 2 = 31


How do you make the 30 using 27 20 5 5?

It is: 5*(27-20)-5 = 30


How do you make 27 from 1 2 4 and 6 using each number only once and each arithmetical operation only once?

4! + 1 x 6 ÷ 2 is one way I can figure without using an operation more than once. 4! = 4 x 3 x 2 x 1 = 24. Then by order of operations, perform 1 x 6 ÷ 2 = 3, which is added to 24 to get 27.Another way is: (6/2)^(4-1), which is 3 raised to the 3 power (3 x 3 x 3 = 27).If the limitation on operators is not present, then you can do it by 4 x 6 + 1 + 2 : 4 x 6 = 24, then add 1 and 2 to get 27.