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What is the factor tree for 27?
In the case of 27, there is only one possible factor tree - using the factors 3 and 9 as the first step. 27 3 x 9 3 x (3x3)
What is 27 using exponents?
27 can be written as 2.70 × 101
How many 3-digit numbers can made using the digits 2 3 4?
If you can repeat a digit, there are 27. If you can't repeat a digit, there are only 6.
What are the factors and prime factors of 27?
The factors of 27 are 1, 3, 9, and 27.The factor pairs of 27 are 1 x 27 and 3 x 9.The proper factors of 27 are 1, 3, and 9 or,if the definition you are using excludes 1, they are 3 and 9.The prime factors of 27 are 3, 3, and 3.Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The only distinct prime factor is 3. The prime factorization of 27 is 3 x 3 x 3 or, in index form (in other words, using exponents), 33.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
How do you make 27 out of four 3 s?
3+3+3x3=27
How do you make 27 from 1 3 4 9 using each number once and only addition multiplication and division?
[Impossible].
How do you make 27 from 1 3 4 and 9 Using each number only once?
3^((4+1)/9)=35/9=243/9=27
How do you get to 27 using the numbers 1 2 4 and 6 only once?
(6*4)+2+1 = 27
How do you make 27 using 1 2 3 and 4 once?
3*(2*4 + 1) = 3*(8 + 1) = 3*9 = 27
How many times does 27 go into 27?
Once only
Sharon uses her initials SLF for her password How many different three-letter passwords can she make with these letters?
Six if using each letter once, or 27 if using a letter more than once.
Who can solve this - Using 1 3 4 and 9 make 27 each number can only be used once and must be used using the following functions plus - x and divide?
This is for a job application...but I think it's impossible. Any takers with an answer?
How do you make 27 using the numbers 1234?
32 -(1+4) =27
How many combinations can you make using only the numbers 1-7?
8
How can you get the number 31 using 9 9 6 3 and 2 only using them once each?
9*9/3 + 6 - 2 = 9*3 + 6 - 2 = 27 + 6 - 2 = 31
How do you make the 30 using 27 20 5 5?
It is: 5*(27-20)-5 = 30
How do you make 27 from 1 2 4 and 6 using each number only once and each arithmetical operation only once?
4! + 1 x 6 ÷ 2 is one way I can figure without using an operation more than once. 4! = 4 x 3 x 2 x 1 = 24. Then by order of operations, perform 1 x 6 ÷ 2 = 3, which is added to 24 to get 27.Another way is: (6/2)^(4-1), which is 3 raised to the 3 power (3 x 3 x 3 = 27).If the limitation on operators is not present, then you can do it by 4 x 6 + 1 + 2 : 4 x 6 = 24, then add 1 and 2 to get 27.
