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Log x is defined only for x > 0.
The first derivative of log x is 1/x, which, for x > 0 is also > 0
The second derivative of log x = -1/x2 is always negative over the valid domain for x.
Together, these derivatives show that log x is a strictly monotonic increasing function of x and that its rate of increase is always decreasing. Consequently log x is convex.
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What is log to the third power equal to?
Log (x^3) = 3 log(x) Log of x to the third power is three times log of x.
Rules of log?
Here are a few, note x>0 and y>0 and a&b not = 1 * log (xy) = log(x) + log(y) * log(x/y) = log(x) - log(y) * loga(x) = logb(x)*loga(b) * logb(bn) = n * log(xa) = a*log(x) * logb(b) = 1 * logb(1) = 0
Log9x plus log x equals 4log10?
log(9x) + log(x) = 4log(10)log(9) + log(x) + log(x) = 4log(10)2log(x) = 4log(10) - log(9)log(x2) = log(104) - log(9)log(x2) = log(104/9)x2 = 104/9x = 102/3x = 33 and 1/3
Log base 2 of x - log base 2 of x-23?
log base 2 of [x/(x - 23)]
If 3 log x - 2 log y?
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