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log(9x) + log(x) = 4log(10)

log(9) + log(x) + log(x) = 4log(10)

2log(x) = 4log(10) - log(9)

log(x2) = log(104) - log(9)

log(x2) = log(104/9)

x2 = 104/9

x = 102/3

x = 33 and 1/3

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Q: Log9x plus log x equals 4log10?
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