Q: How do you solve 14 equals 18 plus y?

Write your answer...

Submit

Still have questions?

Continue Learning about Algebra

-3x+14 = -4 -3x = -4-14 -3x = -18 x = 6

b + 7 = 18 subtract 7 from each side b + 7 - 7 = 18 - 7 b = 11 ----------------check in original equation 11 + 7 = 18 18 = 18 --------------checks

2x - 3y = -4x + 4y = -9from the second equation x = -9-4y , substitute it in the first equation.2(-9-4y)- 3y= -4-18-8y-3y = -4-18-11y = -4-11y = -4+18-11y = 14y = -14/11now, solve for x :x = -9-4yx = -9-4(-14/11)x = -43/11

y= -25

16

Related questions

14 + 18 = 18 + 14 demonstrates the commutative property (of addition).

-14

18+y=32 y=14

You add -18... 18 + y = 32 18 + y + (-18) = 32 + (-18) y = 14

2+14=16

5p-14 = 8p +4 take the 14 to the other side and the 8p to the other side so 5p-8p = 4 +14 -3p = 18 p = -18/3

25-7=18 18/3=6

p + 32

-86

Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.

9 plus 135 = 16 The series is formed by dividing the second number by the first number and then adding 1 to the quotient. 18 ÷ 3 = 6 : 6 + 1 = 7 14 ÷ 7 + 2 : 2 + 1 = 3 18 ÷ 6 = 3 : 3 + 1 = 4 112 ÷ 8 = 14 : 14 + 1 = 15 135 ÷ 9 = 15 : 15 + 1 = 16

2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222