answersLogoWhite

0

To integrate e^(-2x)dx, you need to take a u substitution.

u=-2x

du=-2dx

Since the original integral does not have a -2 in it, you need to divide to get the dx alone.

-(1/2)du=dx

Since the integral of e^x is still e^x, you get:

y = -(1/2)e^(-2x)

Well, that was one method. I usually solve easier functions like this by thinking how the function looked like before it was differentiated. I let f(x) stand for the given function and F(x) stand for the primitive function; the function we had before differentiation (the integrated function).

f(x)= e-2x <-- our given function

F(x)= e-2x/-2 <-- our integrated function

Evidence: F'(x)= -2e-2x/-2 = e-2x = f(x) Q.E.D

It's as simple as that.

User Avatar

Wiki User

13y ago

Still curious? Ask our experts.

Chat with our AI personalities

DevinDevin
I've poured enough drinks to know that people don't always want advice—they just want to talk.
Chat with Devin
ReneRene
Change my mind. I dare you.
Chat with Rene
CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach

Add your answer:

Earn +20 pts
Q: How do you integrate of e -2x?
Write your answer...
Submit
Still have questions?
magnify glass
imp