8x = 120divide the equation by 8
8x/8 = 120/8
x = 15
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8x - 2y-120 = 0 subsitute the x with zero to find the y intercept 0x - 2y-120=0 -2y-120=0 -2y=120 y=60 substitue the y with zero to find the x intercept 8x-120=0 8x=120 x=120/8 x=15 lol hopefully i did this rite... sorry if i didnt XD i have a coordinate geometry test tomorrow... lol
8x = 16 is NOT an 'Inequality#'. However, 8x > 16 is an inequality as is 8x > 16 . NB Treat inequalities as an 'equals'. except for negative numbers or fractions. Hence 8x > 16 Divide both sides by '8' x > 2 Similarly 8x < 16 x < 2
8x = 2x + 15 6x = 15 x = 15/6 = 2.5
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x2 - 8x + 32 = 0 (assuming)you can factor or use the quadratic equation.I recommend the quadratic equation.