8x = 16 is NOT an 'Inequality#'.
However,
8x > 16 is an inequality as is 8x > 16 .
NB Treat inequalities as an 'equals'. except for negative numbers or fractions.
Hence
8x > 16 Divide both sides by '8'
x > 2
Similarly
8x < 16
x < 2
Without an inequality sign it is not an inequality equation but the given expression can be simplified to: 8x-16-7y
p is less than 12.
8x = 120divide the equation by 8 8x/8 = 120/8 x = 15
Solve the inequality and enter your solution as an inequality comparing the variable to the solution. -33+x<-33
-8x -2y = 16 Algebraically rearrange into the form ' y = mx + c'. Hence 2y = -8x - 16 Divide both sides by '2' y = -4x - 8 Hence 'm' the slope is '-4' 'c' the y-intersect is '-8'. NB The equation can be in numerous forms : - -8x - 2y - 16 = 0 8x + 2y + 16 = 0 -8x = 2x + 16
This is not an inequality. There is no <,>, or = sign.
Without an inequality sign it is not an inequality equation but the given expression can be simplified to: 8x-16-7y
You add 8x to each side. This gives you 5 = 16. Since this has no solution, the original equation doesn't have any solution, either.
b -8
You can't simplify that. And you can only calculate a numeric value if you know what values the variables have.
2x2 = 8x x = 8x/2x x = 4 Check: 2(4)2 = 8(4) 2(16) = 32 32 = 32
Yes
To solve the inequality (8x^2 - x < 0), we first factor it as (x(8x - 1) < 0). The critical points are (x = 0) and (x = \frac{1}{8}). Analyzing the sign of the product in the intervals determined by these points, we find that the inequality holds for (0 < x < \frac{1}{8}). Since there are no integer values of (x) in this interval, the number of different integer values of (x) that satisfy the inequality is zero.
X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16
It is an algebraic expression. An inequality includes '>' or '
C. p ‹ 12
First, you have to add 3 to each side to get 8X = 19. Next, you have to divide both sides by 8 to get X = 19/8