x2 - 8x + 32 = 0 (assuming)
you can factor or use the quadratic equation.
I recommend the quadratic equation.
x² + 8x - 48 = (x + 12)(x - 4) x² + 8x + 48 = (4+(√32)i)(4-(√32)i)
x - x2 - 9x + 14 = 0 ; whence, x2 + 8x = 14 , x2 + 8x + 16 = 30 , and x + 4 = ±√30 . Therefore, x = ±√30 - 4 .
x2 - 12x + 32 = 0 x2 - 8x - 4x +32 = 0 x(x -8) - 4(x -8) = 0 (x - 4)(x - 8) = 0 x = 4 or x = 8
x2 + 8x - 5 = 0 ∴ x2 + 8x + 16 = 21 ∴ (x + 4)2 = 21 ∴ x + 4 = ± √21 ∴ x = -4 ± √21
x2 + 12x + 32 = (x + 8)(x + 4)
no
x² + 8x - 48 = (x + 12)(x - 4) x² + 8x + 48 = (4+(√32)i)(4-(√32)i)
X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16
(4 ± i2) where i2 = -1
x - x2 - 9x + 14 = 0 ; whence, x2 + 8x = 14 , x2 + 8x + 16 = 30 , and x + 4 = ±√30 . Therefore, x = ±√30 - 4 .
x2 + 8x + 15 = (x + 3)(x + 5)
x2 + 8x + 15 = (x + 3) (x + 5).
x2 + 8x + 5 = 0 is an expression, not a value, and thus does not actually have a square root. If you are looking to solve for x, then you can say: x2 + 8x + 5 = 0 ∴ x2 + 8x + 16 = 11 ∴ (x + 4)2 = 11 ∴ x + 4 = ±√11 ∴ x = 4 ±√11
x2 + 8x - 2 = 0 => x2 + 8x = 2 => x2 + 8x + 16 = 2 + 16 = 18 => (x + 4)2 = 18 => x + 4 = +or- sqrt(18) = +or- 3*sqrt(2) so x = -4 +or- 3*sqrt(2)
2x+6x=-9 => 8x=-9=> x=-8/9
x2 + 8x - 20 = (x - 2)(x + 10).
x2 + 8x = x(x+8)