4x2 - 9 = (2x + 3)(2x - 3)
9(2x - 1)(2x + 1)
x^2 +8x -9 is equivalent to (x+9)(x-1) when factored
x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.
(9 + 4i)^2 = 9^2 + (2)(9)(4i) +i^2 substitute i^2 for -1; = 81 + 72i -1 = 80 + 72i
y squared minus 9 (y*y)- 9 cannot be solved because there is no given value for 9.
Solve this problem -x squared -40x- 80 =0
Sobtract 1 from minus 9 and get minus 10.
4x2 - 9 = (2x + 3)(2x - 3)
-8.
9(2x - 1)(2x + 1)
(x - 1)(2x - 9)
x=9 squared
It is 5.098
9 minus 8
8M - 4M - 6 - 3 + 5M = 82 - 1 9M - 9 = 64 - 1 9M - 9 = 63 9M - 9 +9 = 63 + 9 9M = 72 9M/9 = 72/9 M = 8
I believe it is prime as you have written it. change the end to + 81 and it factors as (2x - 1)(x-9)(x+9)