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Q: How do you solve 9 x squared minus 1?

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4x2 - 9 = (2x + 3)(2x - 3)

9(2x - 1)(2x + 1)

x^2 +8x -9 is equivalent to (x+9)(x-1) when factored

x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.

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4x2 - 9 = (2x + 3)(2x - 3)

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