Typically in these math questions you will have two equations.
Both equations will have, lets say an x and y value. Two unknown variables.
Take the first equation and rearrange it so that you isolate one of the variables, lets say x.
To isolate x, arrange the equations so that x is on one side, and every other number is on the other.
This expression is equal to x.
Take this expression (all the numbers on opposite side of the side where the x is), and plug it into the second equation. That it, where ever the x appears in the second equation, replace it with this expression.
Solve for y through simple algebra.
Now, take the y value you solved for and plug it into one of the original equations. That is, replace the y in the equation with this number. Solve for x through algebra.
The x and y values you receive are known as the solution.
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To solve the following equation by substitution, we need to have the equal sign. This will help us group the knowns and the unknowns.
Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
You solve this by theoretically diverting the hypotenuse of the x divided by the overall beneficial procedure of y
sub x with 0 and solve
You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.