6(y - 4)
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All you do is set the quadratic function to equal to 0. Then you can either factor or use the quadratic formula to solve for your unknown variable.
There are lots of different types of problems in algebra; you have to learn each type separately. For example, how to add similar expressions; how to multiply expressions; how to factor polynomials; how to solve equations; etc.
Factor the equation and solve for x in each part. x3-4x2-12x Factor out an x right away x (x² - 4x - 12) factor the trinomial x (x - 6) (x + 2) now solve each for y=0 x=0, (x-6=0), (x+2=0) The zeroes (solutions) to the equation are {-2 0 6 }■
cross multiplacation. put the 3 numbers into fractions and than multiply the 2 diagnol numbers then divide by the third.
x2 - 8x + 32 = 0 (assuming)you can factor or use the quadratic equation.I recommend the quadratic equation.