16x = 4 Divide both sides by '16' Hence 16x/16 = 4/16 x = 4 / 16 x = 1/4
16x - 2y = 74 (Eq 1) 2x - 2y = 4 (Eq 2) from Eq 2, 2y = 2x - 4 Substitute in Eq 1 16x - (2x - 4) =74 ie 16x - 2x + 4 = 74 ie 14x = 70 ie x = 5 2y = 2x - 4 = 10 - 4 = 6 y =3 Check 16 x 5 - 2 x 3 = 80 - 6 = 84 QED
4x - 20 = -44x = 16x = 4
In the absence of signs I have assumed the term in 16x and 60 are negative: ie x2 - 16x = -60 or x2 - 16x + 60 = 0 Factors of 60 which total -16 are -6 and -10, so (x - 6)(x - 10)
Divide 28 by 4. X = 7
.25
x2+16x-80 = 0 (x-4)(x+20) = 0 x = 4 or x = -20
16x = 4 Divide both sides by '16' Hence 16x/16 = 4/16 x = 4 / 16 x = 1/4
x2 - 16x + 68 = 5 (x - 8)2 + 4 = 5 (x - 8)2 = 1 x - 8 = 1 or -1 x = 9 or 7
8-16x-32=0 8=16x-32 2x-4=0 2x=4 x=2
16x³ - x = 0 By factorization, we obtain: x(16x² - 1) = 0 x(4x - 1)(4x + 1) = 0 Set each term by 0 and solve for x to get: x = 0 and 4x - 1 = 0 and 4x + 1 = 0 x = {0, ±¼}
8-8x=8x+18 Through simple algebra, this can be manipulated to solve for x: 8=16x+18 -10=16x -5/8=x
16x - 2y = 74 (Eq 1) 2x - 2y = 4 (Eq 2) from Eq 2, 2y = 2x - 4 Substitute in Eq 1 16x - (2x - 4) =74 ie 16x - 2x + 4 = 74 ie 14x = 70 ie x = 5 2y = 2x - 4 = 10 - 4 = 6 y =3 Check 16 x 5 - 2 x 3 = 80 - 6 = 84 QED
4x - 20 = -44x = 16x = 4
If 2x - 16x - 96 = 0, then: -14x = 96 -7x = 48 x = -48/7 Given the wording of your question though, I would guess that you are actually looking for solutions to this equation: 2x2 - 16x -96 = 0 Which we can solve as follows: 2x2 - 16x - 96 = 0 x2 - 8x - 48 = 0 x2 - 12x + 4x - 48 = 0 x(x - 12) + 4(x - 12) = 0 (x + 4)(x - 12) = 0 So x can be equal to either -4 or 12
y=x+4
If: 16x-15-6x = 13 Then: 10x = 28 And: x = 2.8.