T = Distance/R
Congratulations! You already have. h = S+r
If v = r * h then> r = v / h
x = r*cos(theta) y = r*sin(theta) for alpha < theta < alpha + 90 degrees where r is the radius and alpha is any angle (which determines the direction in which the quarter circle is facing).
Since area equals Pi times radius squared take and substitute what is known. 345 equals Pi times the radius squared. divide Pi into both sides for 109.8 equals the radius squared. Now take the square root of 109.8 to get an r of 10.47936 cm.
If X and Y are sides of a right triangle, R is the hypoteneuse, and theta is the angle at the X-R vertex, then sin(theta) is Y / R and cosine(theta) is X / R. It follows, then, that X is R cosine(theta) and Y is R sin(theta)
x2+y2=2y into polar coordinates When converting Cartesian coordinates to polar coordinates, three standard converstion factors must be memorized: r2=x2+y2 r*cos(theta)=x r*sin(theta)=y From these conversions, you can easily get the above Cartesian equation into polar coordinates: r2=2rsin(theta), which reduces down (by dividing out 1 r on both sides) to: r=2sin(theta)
It will be a circle.
area equals pi r squared therefor r squared equals area over pi. Now find square root of r squared and you have "R" (radius) = 2.821
www.mathwords.com about mathwords website feedback Segment of a Circle A part of the interior of a circle bounded by a chord and an arc. 1/2 x R(squared) x ((pi x theta/180) - sin theta) In which R is the circle radius and theta is the angle ( in degrees) which is subtended by the chord (which together with the arc form the boundaries of the partial circle. Note that a value of theta of 180 degrees leads to pi (R squared)/2, or one half the area of a circle.
r2-r-56 factored out equals (r-8)(r+7).
Square root of s, or negative square root of s.
Formula for the volume of a cylinder.
If spherical coords are r and theta, then x = r*cos(theta) and y = r*sin(theta) Conversely, r = sqrt(x2 + y2) and theta = arctan(y/x) provided x is not zero. and theta = 90 deg when x = 0
Written in equation form is: R2 = 5E-5. 5E-5 expressed in decimal form is 0.00005. if you wanted to solve for R, take the square root of 5E-5, which is 0.0070710678.
R^2sin(theta)d(theta)d(phi)(r-hat)
The equation for the radius of circular motion is given by ( r = \frac{{v^2}}{g \cdot \tan(\theta)} ), where ( r ) is the radius of motion, ( v ) is the velocity of the object, ( g ) is the acceleration due to gravity, and ( \theta ) is the angle of bank of the incline.