If X and Y are sides of a right triangle, R is the hypoteneuse, and theta is the angle at the X-R vertex, then sin(theta) is Y / R and cosine(theta) is X / R. It follows, then, that X is R cosine(theta) and Y is R sin(theta)
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y=7+x =x=7-x
T/y = x/wMultiply each side by 'x':Tw/y = x
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.
The x in y=mx+b is the independent variable. You could solve for x, making this a function of y, with simple algebra. y = mx + b y - b = mx (y-b)/m = x
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m