0
What else can I help you with?
How do you solve y equals 7 plus x?
y=7+x =x=7-x
Z2 equals x2 plus y2?
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.
T over y equals x over w solve for x?
T/y = x/wMultiply each side by 'x':Tw/y = x
What is x in y equals mx plus b?
The x in y=mx+b is the independent variable. You could solve for x, making this a function of y, with simple algebra. y = mx + b y - b = mx (y-b)/m = x
How do you Solve the formula y equals mx plus b for M?
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
How do you solve if angle x and angle y are complementary and angle z and angle q are complementary and angle x and angle z are congruent then angle y is congruent to angle q?
x and y are complementary so x + y = 90 and so y = 90 - x z and q are complementary so z + q = 90 and so q = 90 - z x = z so 90 - x = 90 - z that is y = q
Angles X and Y are supplementary and the measure of angle X is 24 degrees greater then the measure of angle Y What is the angle measure?
Okay. If two angles are supplementary then the sum of the two angles is equal to 180. This can be represented in an algebraic equation: X + Y = 180 Now it says the angle X is 24 degrees greater than Y. That can also be written algebraically: Y + 24 = X Now we can subsititute this value for X into the original equation and solve: (Y + 24) + Y = 180 2Y + 24 = 180 2Y = 156 Y = 78 Now that we know angle Y, we can plug this in to either of our formulas in order to discover angle X: X + (78) = 180 X = 102 There you go, angle X is equal to 102o and angle Y is equal to 78o
∠angle, x, and \angle y∠angle, y are supplementary angles. \angle y∠angle, y measures 156^\circ156 What is the measure of \angle x∠xangle, x∘ 156?
for a book cover is this good
A supplement of an angle is four times as large as the angle find the measure of the angle?
You start with two equations y+x=90 and 4x+y=180 and y is the given angle So if you want to figure out what x is you have to substitute an equation for y. so it ends up being 4x+90-x=180 and then you solve for x add the x's and subtract 90 from both sides giving you 3x=90 and then x=30 But you want to get y so you plug it back into the equation y+x=90 So your answer will equal 60. I hope this helps :)
What is the opposite of a supplementary angle?
Y is a supplementary angle to angle X if X + Y = 180 degrees. The only opposite to X + Y = 180 is X + Y ≠180. Such an angle has no specific name.
Wo angles are complementary the second angle measures 32 degrees less than the first angle What is the measure of the first angle?
29 degrees Let x represent the number of degrees of the smaller angle and y the number of degrees of the larger angle. Because the angles are complementary, x+y=90. From the problem, x=y-32. Now solve the equations by substituting x from the second into the first: y-32+y=90 2y-32=90 2y=90+32=122 y=122/2=61 x=y-32=61-32=29
What variable is used for y intercept?
you make x=0 and solve for y. for the x intercept you do y=0 and solve for x
How do you determine x and y in the same mathematical problem?
substitute 0 for y and solve for x. then substitute x for 0 and solve for why and you have the x and y coordinates
What angle is quarter times greater than its supplementary angle?
Angle 100° is quarter times greater than its supplementary angle 80°. Solution: let 'x' be the required angle and 'y' be its complementary angle. x+y=180° Now, x is quarter times greater than y. That is, x=y+¼y. therefore x=y+0.25y =1.25y thus, 1.25y + y = 180° 2.25y = 180° y=80° thus, x=1.25 X 80 =100°
How do you find angles of a triangle with a given slopes?
Slope = Rise/Run = y/x 1. leg = rise = y 2. leg = run = x 3. hypotenuse = √(x^2 + y^2) tan (angle 1) = x/y angle 1 = arctan(x/y) tan (angle 2) = y/x angle 2 = arctan(y/x)
When the sum of the two angle is 180 their difference is 40 What is the angles?
Let x represent the larger angle and y the smaller. Solve the following: x+y=180 x-y=40 The second equation tells us that x=y+40. Plugging this into the first equation, we get, (y+40)+y = 180 2y+40=180 2y=180-40=140 y=140/2=70 So, y=70 and x=70+40=110.
How do you find the x and y intercfept?
Set x = 0 and solve the resulting equation in y for the y-intercept. Set y = 0 and solve the resulting equation in x for the x-intercept.
