0
Add your answer:
Earn +20 pts
How do you solve y equals 7 plus x?
y=7+x =x=7-x
T over y equals x over w solve for x?
T/y = x/wMultiply each side by 'x':Tw/y = x
Z2 equals x2 plus y2?
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.
What is x in y equals mx plus b?
The x in y=mx+b is the independent variable. You could solve for x, making this a function of y, with simple algebra. y = mx + b y - b = mx (y-b)/m = x
How do you Solve the formula y equals mx plus b for M?
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
How do you solve if angle x and angle y are complementary and angle z and angle q are complementary and angle x and angle z are congruent then angle y is congruent to angle q?
x and y are complementary so x + y = 90 and so y = 90 - x z and q are complementary so z + q = 90 and so q = 90 - z x = z so 90 - x = 90 - z that is y = q
Angles X and Y are supplementary and the measure of angle X is 24 degrees greater then the measure of angle Y What is the angle measure?
Okay. If two angles are supplementary then the sum of the two angles is equal to 180. This can be represented in an algebraic equation: X + Y = 180 Now it says the angle X is 24 degrees greater than Y. That can also be written algebraically: Y + 24 = X Now we can subsititute this value for X into the original equation and solve: (Y + 24) + Y = 180 2Y + 24 = 180 2Y = 156 Y = 78 Now that we know angle Y, we can plug this in to either of our formulas in order to discover angle X: X + (78) = 180 X = 102 There you go, angle X is equal to 102o and angle Y is equal to 78o
∠angle, x, and \angle y∠angle, y are supplementary angles. \angle y∠angle, y measures 156^\circ156 What is the measure of \angle x∠xangle, x∘ 156?
for a book cover is this good
What is the opposite of a supplementary angle?
Y is a supplementary angle to angle X if X + Y = 180 degrees. The only opposite to X + Y = 180 is X + Y ≠180. Such an angle has no specific name.
A supplement of an angle is four times as large as the angle find the measure of the angle?
You start with two equations y+x=90 and 4x+y=180 and y is the given angle So if you want to figure out what x is you have to substitute an equation for y. so it ends up being 4x+90-x=180 and then you solve for x add the x's and subtract 90 from both sides giving you 3x=90 and then x=30 But you want to get y so you plug it back into the equation y+x=90 So your answer will equal 60. I hope this helps :)
Wo angles are complementary the second angle measures 32 degrees less than the first angle What is the measure of the first angle?
29 degrees Let x represent the number of degrees of the smaller angle and y the number of degrees of the larger angle. Because the angles are complementary, x+y=90. From the problem, x=y-32. Now solve the equations by substituting x from the second into the first: y-32+y=90 2y-32=90 2y=90+32=122 y=122/2=61 x=y-32=61-32=29
What variable is used for y intercept?
you make x=0 and solve for y. for the x intercept you do y=0 and solve for x
How do you determine x and y in the same mathematical problem?
substitute 0 for y and solve for x. then substitute x for 0 and solve for why and you have the x and y coordinates
What angle is quarter times greater than its supplementary angle?
Angle 100° is quarter times greater than its supplementary angle 80°. Solution: let 'x' be the required angle and 'y' be its complementary angle. x+y=180° Now, x is quarter times greater than y. That is, x=y+¼y. therefore x=y+0.25y =1.25y thus, 1.25y + y = 180° 2.25y = 180° y=80° thus, x=1.25 X 80 =100°
How do you find angles of a triangle with a given slopes?
Slope = Rise/Run = y/x 1. leg = rise = y 2. leg = run = x 3. hypotenuse = √(x^2 + y^2) tan (angle 1) = x/y angle 1 = arctan(x/y) tan (angle 2) = y/x angle 2 = arctan(y/x)
How do you find the x and y intercfept?
Set x = 0 and solve the resulting equation in y for the y-intercept. Set y = 0 and solve the resulting equation in x for the x-intercept.
How do you solve for x in a angle in a double angle?
lol hahaha
