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How do you solve for x and y in an angle?

Updated: 4/28/2022
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14y ago

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If X and Y are sides of a right triangle, R is the hypoteneuse, and theta is the angle at the X-R vertex, then sin(theta) is Y / R and cosine(theta) is X / R. It follows, then, that X is R cosine(theta) and Y is R sin(theta)

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Q: How do you solve for x and y in an angle?
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How do you solve if angle x and angle y are complementary and angle z and angle q are complementary and angle x and angle z are congruent then angle y is congruent to angle q?

x and y are complementary so x + y = 90 and so y = 90 - x z and q are complementary so z + q = 90 and so q = 90 - z x = z so 90 - x = 90 - z that is y = q


Angles X and Y are supplementary and the measure of angle X is 24 degrees greater then the measure of angle Y What is the angle measure?

Okay. If two angles are supplementary then the sum of the two angles is equal to 180. This can be represented in an algebraic equation: X + Y = 180 Now it says the angle X is 24 degrees greater than Y. That can also be written algebraically: Y + 24 = X Now we can subsititute this value for X into the original equation and solve: (Y + 24) + Y = 180 2Y + 24 = 180 2Y = 156 Y = 78 Now that we know angle Y, we can plug this in to either of our formulas in order to discover angle X: X + (78) = 180 X = 102 There you go, angle X is equal to 102o and angle Y is equal to 78o


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29 degrees Let x represent the number of degrees of the smaller angle and y the number of degrees of the larger angle. Because the angles are complementary, x+y=90. From the problem, x=y-32. Now solve the equations by substituting x from the second into the first: y-32+y=90 2y-32=90 2y=90+32=122 y=122/2=61 x=y-32=61-32=29


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