It will be a circle.
I regret that the browser provided by answers.com is incapable of displaying even simple graphics.
Yes. (Theta in radians, and then approximately, not exactly.)
theta = arcsin(0.0138) is the principal value.
x2+y2=2y into polar coordinates When converting Cartesian coordinates to polar coordinates, three standard converstion factors must be memorized: r2=x2+y2 r*cos(theta)=x r*sin(theta)=y From these conversions, you can easily get the above Cartesian equation into polar coordinates: r2=2rsin(theta), which reduces down (by dividing out 1 r on both sides) to: r=2sin(theta)
It also equals 13 12.
I regret that the browser provided by answers.com is incapable of displaying even simple graphics.
It's possible
Yes. (Theta in radians, and then approximately, not exactly.)
theta = arcsin(0.0138) is the principal value.
x2+y2=2y into polar coordinates When converting Cartesian coordinates to polar coordinates, three standard converstion factors must be memorized: r2=x2+y2 r*cos(theta)=x r*sin(theta)=y From these conversions, you can easily get the above Cartesian equation into polar coordinates: r2=2rsin(theta), which reduces down (by dividing out 1 r on both sides) to: r=2sin(theta)
Yes, it is.
It also equals 13 12.
Theta equals 0 or pi.
If sine theta is 0.28, then theta is 16.26 degrees. Cosine 2 theta, then, is 0.8432
No.
The answer depends on what theta is and the units of its measurement.
Another way to classify a point is with the polar system. A polar coordinate, instead of (x, y), is (r, theta). To find r, you can use the Pythagorean Theorem, a^2 + b^2 = c^2.In this case, a = 2 and b = 4, or vice versa. That means that c, or r, equals 2 square roots of 5, or 2sqrt5.To find theta, you can use this formula: theta = tan inverse(y/x). With point (2,4), theta equals approximately 63.43 degrees, or 514394/8109This, as a polar coordinate, is (2sqrt5, (514394/8109))Using the polar system, however, you can express this point in infinitely many different ways. Just add/subtract 360 degrees to/from theta and you have the same point again.