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To split a circle into 11 equal parts using 4 lines, you would first draw two diameters perpendicular to each other, creating four equal parts. Next, draw a line from the center of the circle to a point on the circumference, dividing each of the four sections in half, resulting in eight equal parts. Finally, draw two more lines from the center to points on the circumference, dividing each of the eight sections in half again, resulting in a total of 11 equal parts.
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TaigaHere's the link with the picture:
http://mathforum.org/library/drmath/view/57858.html
The trick is to have one x over the other, such that the intersect point of the second x is above the intersect point of the first x. Do his right, and you'll have what looks like a Star Trek emblem in the middle, comprised of three sections. It will be surrounded by eight other sections.
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What is the maximum number of parts a circle can be divided by using four straight lines?
11
How do you divide a rectangle into 8 equal parts using only 3 lines?
have have to divide them
Divide a rectangle into 7 parts with only 3 lines?
To divide a rectangle into 7 parts using 3 lines: Use 2 lines to draw two diagonals. Use the third line to draw a parallel line to any of the sides but not passing through the centre. This will create 7 parts in the rectangle.
How do you divide a circle into five equal parts?
If a circle is comprised of 360 degrees, then each of the five sections will encompass 72 degrees. From an arbitrary radius, using a protractor, measure 72 degrees, then continue around the circle.
How do you divide a circle in to 6th equal parts?
If you have a protractor: Draw a line from the center of the circle to the outside (radius), then measure 60 degrees and draw another line. If you have a compass: Draw a circle using the compass, then, using your compass, place the compass needle on the edge of the circle, draw another circle (KEEP THE RADIUS THE SAME). Your two circles should have two intersection points. Place the needle on one of the intersection points and repeat the process. I suggest you look at:
