5x-2 = 3x-6 5x = 3x - 6 +2 5x = 3x - 4 5x - 3x = -4 2x = -4 x = -2
5x - 2y = 05x - 5x - 2y = 0 - 5x-2y = - 5x(-2y)/-2 = (-5x)/-2y = (5/2)x where the slope is 5/2 and the y-intercept is 0.
It is: 10x^2 -4x = 2x(5x-2)
7
10x ÷ 5x = 2
Here is the work for that problem: 5x+ 2=12 5x= 12-2 5x=10 x= 2
-6 = 3 x -2 13 = 5 x 3 - 2 → 5x² + 13x - 6 = (5x - 2)(x + 3)
5x-1+2= 5x+1
the question is to solve (x^2-5x+5)^(x^2-36)=1
5x + 2 = 22 5x = 22 - 2 5x = 20 5x/5 = 20/5 x=4
5x-2 = 3x-6 5x = 3x - 6 +2 5x = 3x - 4 5x - 3x = -4 2x = -4 x = -2
25x'2
3
You can use 1/2? 1/2((150x4)-24) I think that'd work but I'm not sure
If your equation is 5x-2=4x+4 Then this is how you solve it... 5x-2=4x+4 5x-2+2=4x+4+2 5x=4x+6 5x-4x=4x-4x+6 x=6 Your x=6
If: y = 5x and y = 3 -x Then: 5x = 3 -x => 5x +x = 3 => 6x = 3 => x = 1/2 By substitution point of contact is at: (1/2, 5/2)
If you mean 5x+2 = 12 then 5x = 10 and the value of x is 2