x3 + 5x2 - x - 5 = (x2 - 1)(x + 5) = (x + 1)(x - 1)(x + 5)
5x2-18x+9 = (5x-3)(x-3)
(5x - 3)(x - 3)
x^2 + 3x - 2; -x^2 - 3x + 2andx - 1; 1 - x
x3-5x2+x is already simplified.
5x2 + 20x = 5x (x + 4)
5x2 + 9x + 4 = (x + 1)(5x + 4).
5x2 - 14x + 8 = 5x2 - 10x - 4x + 8 = 5x(x-2) - 4(x-2) = (5x-4)*(x-2)
5x2-46x+9 = (5x-1)(x-9)
(5x - 1)(x + 3)5x2 + 14x - 3= 5x2 + 15x - x - 3= 5x(x + 3) - 1(x + 3)= (5x - 1)(x + 3)
Distance travelled = 5x3 - 6x2 + 3x + 14 = 5x3 + 5x2 - 11x2 - 11x + 14x + 14 = 5x2(x + 1) - 11x(x + 1) + 14(x + 1) = (x + 1)(5x2 - 11x + 14) Then time = distance/rate = (x + 1)(5x2 - 11x + 14) / (x+1) = 5x2 - 11x + 14
If that's 5x2, it factors to (x + 5)(x2 + 1)
x3 + 5x2 - x - 5 = (x2 - 1)(x + 5) = (x + 1)(x - 1)(x + 5)
By splitting the Middle Term, 5X2 + 25X + 4X +20 5X(X+5) + 4(X+5) (5X+4)(X+5)
x(5x + 7)
It is -10.
5x(x+3)