15 cm
Solved through Pythagoras' theorem.
Easiest thing to do here would be to draw a diagram and label the sides with their lengths and draw a line for the diagonal. You can see the diagonal forms part of a right-angled triangle, with its shorter lengths 35 cm and 12 cm. So using Pythagoras's Theorem, x2 = 352 + 122 = 1369 x = square root of 1369 = 37 cm.
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^
34cm
Without any further information regarding the rectangle, any two numbers that multiply to get 108 will suffice: 1cm x 108cm 2cm x 58cm 3cm x 36cm 4cm x 27cm 6cm x 18cm 9cm x 12cm Plus if the sides are allowed to not be whole numbers, there are many, many more. For example: 10cm x 10.8cm 5cm x 21.6cm
12+12=24 8+8= +16 The perimeter =40cm2
The area of rectangle is : 72.0
12cm
area = length x width area = 12 x 10 = 120 square cm
36 cm2 Area of a rectangle is length times width, so you would multipy 12cm by 3 cm to get 36 sq. (squared) cm.
The length of the other diagonal works out as 12cm
12cm x 12cm
Area = 108cm2 Width = 12cm Length = 9cm
Perimeter of a rectangle = 2 x length + 2 x width. 52 = 2l + 2 x 12 = 2l + 24 (Where l is the length) 2l = 52 - 24 = 28 length = 28/2 = 14 cm
12cm is not uncommon.
the equation for area is area = length * width. area = 3cm*4cm. Area = 12cm^2
Answerfirst you have to make it a square by subtracting 2cms from the length and adding 2cms to the width. That will make it equal to 12cm. The area for the rectangle was 140cm then it increased by 4 because 12cm * 12cm is 144cm. so x = 2 and the area increases by four.
A rectangle or perhaps a parallelogram