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Oh, dude, there are 90 two-digit numbers you can make from 0 to 9. You've got 10 options for the first digit (0-9) and 9 options for the second digit (0-9 excluding the one you already picked for the first digit). So, like, 10 times 9 equals 90. Math can be fun when you're making numbers do the cha-cha.
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Maxine
JudyWell honey, there are 90 two-digit numbers that can be formed from 0 to 9. You see, you've got 10 choices for the tens digit (0-9) and 10 choices for the ones digit (0-9), giving you a total of 10 x 10 = 100 possible numbers. But we gotta subtract 10 numbers where both digits are the same (like 11, 22, 33, you get the idea), so that leaves us with 90 unique two-digit numbers. Hope that clears things up for ya!
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How many five digit numbers can be formed by 1234 and 5?
9,999 different combos well 10,00 if you add 0 in with it
How many 4 digit numbers can be formed using 0 1 2 3 4 5 6 7 8 and 9 as many times as possible?
10,000
How many positive three digit integers can be formed such that the hundreds digit is equal to the sum of the tens digit and ones digit?
start with the 100's place 0 = 0+0 1 = 1+0 = 0+1 2 = 1+1=2+0=0+2 3 = 3+0 = 2+1 = 1+2 = 0+3 ... with the 100's digit, the number of such numbers is one greater than that number 0 : 1 1 : 2 ... therefore there are 1+2+3+4+5+6+7+8+9+10 = 5*11 = 55 such numbers unless you don't count 000 as a three digit number, then there are 54 such numbers.
How many 4 digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if repetitions of digits are allowed?
10,000
How many 4 digit numbers can be formed by the digits 1234567890?
Oh, what a happy little question! With the digits 1-9 and 0, you have 10 options for each digit in a 4-digit number. So, you can form 10 x 10 x 10 x 10 = 10,000 different 4-digit numbers. Isn't that just delightful? Just imagine all the beautiful combinations you can create!
