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How many 6 digit numbers can be formed that contains no zeros two times the digit 1 two times the digit 2?

16000


How many 4 digit numbers can be formed using 1 2 3 4 5 6 7 8 and 9 as many times as possible?

6,561


How many 5 digit numbers containing two times the digit 6 can be formed from the digits 123456?

No digit that is 5 places long is equal to 6 times 2 other than 12.000


How many 2 digit numbers can be formed from 0 to 9?

Oh, dude, there are 90 two-digit numbers you can make from 0 to 9. You've got 10 options for the first digit (0-9) and 9 options for the second digit (0-9 excluding the one you already picked for the first digit). So, like, 10 times 9 equals 90. Math can be fun when you're making numbers do the cha-cha.


How many numbers can be formed using 2 3 4 and 5 as many times as possible?

there are 22


How many 3 digit numbers can be formed from the digits 1 2 3 4 5 6 7 8 9 if each digit is used only once?

Multiply the number of possible starting numbers by the number of possible middle numbers by the number of possible end numbers to get your result.In example, The possible starting numbers are 1, 2, 3, 4, 5, 6, 7, 8, and 9. Let's say I picked nine as the starting number. Since your question states that each number can only be used once, we eliminate nine from the selection of middle and end numbers. Now, the choices for the possible middle and end numbers are 1, 2, 3, 4, 5, 6, 7, and 8.Possible starting numbers= 9Possible middle numbers= 8Multiply 9 by 8. You get 72 different choices for a two digit number.Let's say that the middle number I picked was two. We then remove the number two from the possible choices for the final numbeselections: 1, 3, 4, 5, 6, 7, and 8.Possible outcomes for two digit number= 72 (which is 9 times 8)Possible end numbers = 7Multiply 72 by 7 to get the possible outcomes for a three digit number with each digit used only once.72 times 7 = 504. You have 504 possible outcomes.


How many four digits can be formed in 1 2 3 4 5 and 6 without repeating the numbers?

To form a four-digit number using the digits 1, 2, 3, 4, 5, and 6 without repeating any digits, you can choose the first digit in 6 ways, the second digit in 5 ways, the third digit in 4 ways, and the fourth digit in 3 ways. Therefore, the total number of four-digit combinations is calculated as (6 \times 5 \times 4 \times 3 = 360). Thus, 360 different four-digit numbers can be formed.


What is the number if there is a 4 digit number no numbers are repeated the digit is odd the digit in the tens place is three times the digit in the thousands place and the sum of the numbers is 27?

3897


How do you multiply by 2 or 3 digit numbers?

first digit time second digit and second digit times first digit then repeat


How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?

How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?


Start with a three-digit number in which the digits are all different Use the digits to make all possible two-digit numbers and obtain their sum Investigate?

The sum is 22 times the sum of the three digits.


How many times does the digit 9 appear in the numbers from 1 to 100?

11 times