answersLogoWhite

0

start with the 100's place

0 = 0+0

1 = 1+0 = 0+1

2 = 1+1=2+0=0+2

3 = 3+0 = 2+1 = 1+2 = 0+3

...

with the 100's digit, the number of such numbers is one greater than that number

0 : 1

1 : 2

...

therefore there are 1+2+3+4+5+6+7+8+9+10 = 5*11 = 55 such numbers

unless you don't count 000 as a three digit number, then there are 54 such numbers.

User Avatar

Wiki User

13y ago

What else can I help you with?

Related Questions

How many positive 3-digit integers can be formed that the 100s digit is equal to the sum of the 10s and 1s digit?

54


How many four digit positive integers are there with thousands digit 2?

There are one thousand. Starting at 2000 and going to 2999


How may two digit-numbers contain the digit 4?

18 positive integers and 36 integers (negative and positive)


How many different positive four digit integers can be formed if the first digit must be even the last digit must be odd and all digits must be distinct?

There are 320 such numbers.


How many two-digit positive integers are there?

90


What is the number of 2 digit positive integers?

44


You are a 4 digit number your hundreds digit number is triple your thousands digit the number formed by your tens and ones digit is triple the number formed by your thousands and hundreds digits?

1339


How many one digit integers are there?

There are 10 one digit positive integers (0 - 9) and 9 one digit negative integers (-9 to -1) making 19 in all.


How many positive three-digit integers are divisible by neither 2 or 3?

the range of three-digit integers is from 100 to 999. Therefore, there are 300 positive three-digit integers that are divisible by neither 2 nor 3.1 day ago


How many positive integers less than 1000 have distinct digits and are even?

To determine the number of positive integers less than 1000 with distinct digits and are even, we need to consider the possible combinations of digits. Since the number must be even, the last digit must be even, giving us 5 options (0, 2, 4, 6, 8). For the hundreds digit, we have 9 options (1-9), and for the tens digit, we have 8 options (0-9 excluding the hundreds digit and the last digit). Therefore, the total number of such integers is 5 * 9 * 8 = 360.


How many 3-digit positive integers are there?

the answer would be 900


How many positive two-digit integers is the ones digit greater than twice the tens digit?

4