Instead of going from 1 to 500, let's just subtract one from the set and come up with "How many 3's appear from 1 to 499?"
Total possible combinations in this, including leading zeros, is 5*10*10, i.e. 5 possible in the first set(0,1,2,3,4), and 10 in the second two(0,1,2,,4,5,6,7,8,9).
Instead of figuring out how many have a 3, lets figure out how many don't. Well there is 4 possibilities in the first (0,1,2,4), and nine in the second two (0,1,2,4,5,6,7,8,9).
So, total = 5 * 10 * 10 = 500
Without 3 = 4 * 9 * 9 = 324
500-324 = 176
There are 176 numbers from 1 to 500 that have the digit 3 in them.
There are 29 3s because there also a 3 in the how many 3s are in 83333333333333333333333333333
That is incorrect. The common factors of 500 and 256 are 1, 2, 4.
30 times because when you count up in tens this is the answer
Interest rate (also called the rate of return). For example: What is the interest rate on a 10,000$ principle investment that pays 500$ after one year? 10000 * r = 500 r = 500 / 10000 r = .05 = 5% Check: 10000$ @ 5%/1 yr = i 10000 * 5/100 = i 10000 * .05 = 500 ($ Interest at the end of 1 yr) 500 = 500 = true! ======== Response 1: what is the answer d. percent of change
50/500 as a fraction in lowest terms is 1/10
200
Zero. Only the digits 5 and 0 appear in 500.
900
200
200
3s + 1
200
200
95
are you asking how many 1/3s are in 6, or 6 divided by 3?there are 18 1/3s in 6 (6x3)6 divided by 3 is 2
-7 = 3s - 1 +1 +1 (add 1 to both sides to get the variable alone) ___ ____ -6 = 3s __ ___ (-6 and 3s both divided by 3) 3 3 -2 = s
There are three thirds (1/3s) in every whole, so there are six thirds in two wholes.