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To determine how many times the digit 3 appears from 1 to 500, we need to consider each place value separately. In the units place, the digit 3 appears 50 times (3, 13, 23, ..., 493). In the tens place, the digit 3 appears 5 times in each set of 10 numbers (30, 31, 32, ..., 39), totaling 50 times. In the hundreds place, the digit 3 appears 100 times (300, 301, 302, ..., 399). Therefore, the digit 3 appears 200 times from 1 to 500.
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TaigaInstead of going from 1 to 500, let's just subtract one from the set and come up with "How many 3's appear from 1 to 499?"
Total possible combinations in this, including leading zeros, is 5*10*10, i.e. 5 possible in the first set(0,1,2,3,4), and 10 in the second two(0,1,2,,4,5,6,7,8,9).
Instead of figuring out how many have a 3, lets figure out how many don't. Well there is 4 possibilities in the first (0,1,2,4), and nine in the second two (0,1,2,4,5,6,7,8,9).
So, total = 5 * 10 * 10 = 500
Without 3 = 4 * 9 * 9 = 324
500-324 = 176
There are 176 numbers from 1 to 500 that have the digit 3 in them.
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How many 3s are in 83333333333333333333333333333?
There are 29 3s because there also a 3 in the how many 3s are in 83333333333333333333333333333
What numbers go into 500 and 256?
That is incorrect. The common factors of 500 and 256 are 1, 2, 4.
How many times does the digit 0 appear between 1 to 300?
30 times because when you count up in tens this is the answer
The term rate in percent problems refers to the?
Interest rate (also called the rate of return). For example: What is the interest rate on a 10,000$ principle investment that pays 500$ after one year? 10000 * r = 500 r = 500 / 10000 r = .05 = 5% Check: 10000$ @ 5%/1 yr = i 10000 * 5/100 = i 10000 * .05 = 500 ($ Interest at the end of 1 yr) 500 = 500 = true! ======== Response 1: what is the answer d. percent of change
How do you write 50 over 500 in simplest terms?
50/500 as a fraction in lowest terms is 1/10
